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Asymptotes and Graph Behavior

Nov 19, 2025

Overview

The transcript explains how to find and graph vertical, horizontal, and slant (oblique) asymptotes of rational functions, along with domain, range, intercepts, holes, and end behavior.

Asymptotes: Concepts and Rules

  • Vertical asymptote (VA): Set denominator equal to zero; exclude any factor that cancels with numerator.
  • Horizontal asymptote (HA):
    • Bottom heavy (deg numerator < deg denominator): y = 0.
    • Same degree: y = ratio of leading coefficients.
    • Top heavy (deg numerator > deg denominator): no HA; if degree difference is 1, a slant asymptote exists.
  • Slant/oblique asymptote (SA): Use polynomial long division when deg(numerator) = deg(denominator) + 1; quotient (without remainder) gives y = mx + b.
  • End behavior: y approaches the horizontal asymptote (or follows the slant asymptote) as x β†’ ±∞.

Worked Example 1: y = 1/(x βˆ’ 3)

  • Vertical asymptote: x = 3.
  • Horizontal asymptote: y = 0 (bottom heavy).
  • End behavior: y β†’ 0 as x β†’ ±∞.
  • Graph placement via test points:
    • x = 4 β†’ y = 1 β†’ right branch above x-axis.
    • x = 2 β†’ y = βˆ’1 β†’ left branch below x-axis.
  • Domain: (βˆ’βˆž, 3) βˆͺ (3, ∞).
  • Range: (βˆ’βˆž, 0) βˆͺ (0, ∞).

Worked Example 2: y = 1/(x + 2) + 7

  • Vertical asymptote: x = βˆ’2.
  • Horizontal asymptote: y = 7 (y = 0 shifted up by 7).
  • Graph placement via test points:
    • x = βˆ’1 β†’ y = 8 β†’ right of VA, above HA.
    • x = βˆ’3 β†’ y = βˆ’6 β†’ left of VA, below HA.
  • Domain: (βˆ’βˆž, βˆ’2) βˆͺ (βˆ’2, ∞).
  • Range: (βˆ’βˆž, 7) βˆͺ (7, ∞).

Worked Example 3: y = (6x βˆ’ 18)/(2x + 4)

  • Simplification/factoring: y = [6(x βˆ’ 3)]/[2(x + 2)].
  • Horizontal asymptote: y = 3 (same degree; 6x/2x = 3).
  • Vertical asymptote: x = βˆ’2.
  • Intercepts:
    • x-intercept: set numerator 0 β†’ x = 3 β†’ (3, 0).
    • y-intercept: x = 0 β†’ y = βˆ’18/4 = βˆ’4.5 β†’ (0, βˆ’4.5).
  • Placement check: x = βˆ’3 β†’ y = 18 (above HA on left).
  • Domain: (βˆ’βˆž, βˆ’2) βˆͺ (βˆ’2, ∞).
  • Range: (βˆ’βˆž, 3) βˆͺ (3, ∞).

Worked Example 4: y = (2x^2 βˆ’ 3x βˆ’ 2)/(x^2 + x βˆ’ 6)

  • Factor:
    • Denominator: x^2 + x βˆ’ 6 = (x + 3)(x βˆ’ 2).
    • Numerator: 2x^2 βˆ’ 3x βˆ’ 2 = (2x + 1)(x βˆ’ 2) via grouping.
  • Cancellation and hole:
    • Cancel (x βˆ’ 2); hole at x = 2.
    • Hole coordinate: plug x = 2 into surviving y = (2x + 1)/(x + 3) β†’ y = 1 β†’ hole at (2, 1).
  • Horizontal asymptote: y = 2 (same degree; 2x^2/x^2).
  • Vertical asymptote: x = βˆ’3 (surviving denominator factor).
  • Domain: (βˆ’βˆž, βˆ’3) βˆͺ (βˆ’3, 2) βˆͺ (2, ∞) (remove VA and hole x-value).
  • Range: (βˆ’βˆž, 1) βˆͺ (1, 2) βˆͺ (2, ∞) (remove hole y-value and HA).

Worked Example 5: y = (2x^2 βˆ’ x + 1)/(x βˆ’ 2)

  • Vertical asymptote: x = 2 (denominator zero; numerator not factorable to cancel).
  • Horizontal asymptote: none (top heavy).
  • Slant asymptote via long division:
    • Quotient: 2x + 3 with remainder 7 β†’ SA: y = 2x + 3.
  • Placement via points:
    • x = 0 β†’ y = 1/(βˆ’2) = βˆ’0.5 β†’ left branch below SA.
    • x = 3 β†’ y = 16 β†’ right branch above SA.

Summary Table of Examples

FunctionVAHASAHole(s)Key PointsDomainRange
y = 1/(x βˆ’ 3)x = 3y = 0nonenone(4, 1), (2, βˆ’1)(βˆ’βˆž, 3) βˆͺ (3, ∞)(βˆ’βˆž, 0) βˆͺ (0, ∞)
y = 1/(x + 2) + 7x = βˆ’2y = 7nonenone(βˆ’1, 8), (βˆ’3, βˆ’6)(βˆ’βˆž, βˆ’2) βˆͺ (βˆ’2, ∞)(βˆ’βˆž, 7) βˆͺ (7, ∞)
y = (6x βˆ’ 18)/(2x + 4)x = βˆ’2y = 3nonenone(3, 0), (0, βˆ’4.5), (βˆ’3, 18)(βˆ’βˆž, βˆ’2) βˆͺ (βˆ’2, ∞)(βˆ’βˆž, 3) βˆͺ (3, ∞)
y = (2x^2 βˆ’ 3x βˆ’ 2)/(x^2 + x βˆ’ 6)x = βˆ’3y = 2none(2, 1)Surviving y = (2x + 1)/(x + 3)(βˆ’βˆž, βˆ’3) βˆͺ (βˆ’3, 2) βˆͺ (2, ∞)(βˆ’βˆž, 1) βˆͺ (1, 2) βˆͺ (2, ∞)
y = (2x^2 βˆ’ x + 1)/(x βˆ’ 2)x = 2noney = 2x + 3none(0, βˆ’0.5), (3, 16)(βˆ’βˆž, 2) βˆͺ (2, ∞)not specified

Key Terms & Definitions

  • Vertical asymptote (VA): A vertical line x = a where the function grows without bound near x = a.
  • Horizontal asymptote (HA): A horizontal line y = b that the function approaches as x β†’ ±∞.
  • Slant (oblique) asymptote (SA): A non-horizontal line y = mx + b approached by the function as x β†’ ±∞.
  • Bottom heavy: deg(numerator) < deg(denominator); HA is y = 0.
  • Top heavy: deg(numerator) > deg(denominator); no HA; if degree difference is 1, SA exists.
  • Hole (removable discontinuity): A point (a, b) removed from the graph due to a common factor cancellation.
  • End behavior: The limiting value or line the function approaches as x β†’ ±∞.

Action Items / Next Steps

  • Practice identifying degree relationships to choose HA or SA quickly.
  • Factor numerators and denominators fully to detect holes before assigning VAs.
  • Use long division for top-heavy cases with degree difference of one to find SA.
  • Confirm graph branch locations with test points on each side of the VA.