Overview
- Topic: Volumes of solids using the methods of slicing: Discs and Washers.
- Goal: Use Riemann-sum idea to derive integrals that compute volumes by adding cross-sectional areas.
- Main methods covered: Volume by slicing (general), Discs (solid of revolution about axis), Washers (hollow solids), and application to rotations about x- and y-axes and about horizontal lines.
Key Concepts
- Volume by slicing:
- Cut a solid into thin slabs (slices) perpendicular to an axis.
- Volume of one slab ≈ (cross-sectional area at xk) * Δx.
- Sum slabs and take limit as Δx → 0 to get integral: V = ∫[a→b] A(x) dx.
- Cross-sectional area:
- For slices perpendicular to x-axis: A(x) is area of cross-section at x.
- For slices perpendicular to y-axis: A(y) is area of cross-section at y.
- Discs method (solids of revolution without hole):
- Cross-section is a circle with radius r(x) = f(x) when revolving y = f(x) about x-axis.
- Formula: V = ∫[a→b] π [f(x)]^2 dx.
- If revolving about y-axis, use functions expressed as x = u(y): V = ∫[c→d] π [u(y)]^2 dy.
- Washers method (solids of revolution with hole):
- Outer radius R(x) from the axis, inner radius r(x) from axis.
- Cross-sectional area = π[R(x)]^2 − π[r(x)]^2 = π( R^2 − r^2 ).
- Formula: V = ∫[a→b] π ( [outer radius]^2 − [inner radius]^2 ) dx (or dy if perpendicular to y).
- Important setup rules:
- Discs/Washers: express functions in terms of the variable corresponding to the axis perpendicular to slices (revolve about x-axis → functions in x; revolve about y-axis → functions in y).
- Identify interval [a,b] by intersection points of bounding curves or given bounds.
- Determine which curve gives the outer radius (top or right as appropriate) and which gives inner radius (bottom or left).
- Simplify algebra before integrating.*
Formulas and Definitions
- Volume by slicing (general): V = ∫[a→b] A(x) dx.
- Disc method (about x-axis): V = ∫[a→b] π [f(x)]^2 dx.
- Disc method (about y-axis): V = ∫[c→d] π [u(y)]^2 dy.
- Washer method (about x-axis): V = ∫[a→b] π ( [F(x)]^2 − [G(x)]^2 ) dx (F outer, G inner).
- Washer method (about y-axis): V = ∫[c→d] π ( [U(y)]^2 − [V(y)]^2 ) dy.
When revolving about a horizontal line y = k:
- Outer radius = distance from line y = k to outer curve = |k − y_outer(x)|.
- Inner radius = distance from line y = k to inner curve = |k − y_inner(x)|.
- Then use washers with those radii squared and integrated over x (if slices perpendicular to x).
Worked Example Summaries
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Example 1 (simple cylinder-like stack):
- Region: cross-section is a circle of radius 1, x from 1 to 5.
- A(x) = π(1)^2 = π → V = ∫[1→5] π dx = 4π.
- Matches cylinder volume formula base area * height.
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Example 2 (disc method, y = 3√x from x=1 to 4, about x-axis):
- Setup: V = ∫[1→4] π [3√x]^2 dx = ∫[1→4] 9π x dx.
- Integrate: 9π * (x^2/2)|1^4 = (9π/2)(16 − 1) = (9π/2)*15 = 135π/2.
-
Example 3 (derive sphere volume by discs):
- Start with upper semicircle: y = √(R^2 − x^2), x ∈ [−R, R], revolve about x-axis.
- Disc radius = y = √(R^2 − x^2).
- V = ∫[−R→R] π (R^2 − x^2) dx.
- Integrate and simplify to V = (4/3)Ï€ R^3.
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Example 4 (washer method, region between f(x) and g(x) rotated about x-axis):
- Given: region between y = f(x) and y = g(x) for x ∈ [a,b]. If f(x) ≥ g(x).
- V = ∫[a→b] π( f(x)^2 − g(x)^2 ) dx.
- Worked numeric: region between y = x^2 + 1/4 and y = x^2 for x ∈ [0,2] led to simplified integrand and final numeric volume (including factor π).
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Example 5 (disc about y-axis using x = u(y)):
- y = x with y ∈ [0,2], revolve about y-axis.
- Solve for x in terms of y: x = y.
- V = ∫[0→2] π [x(y)]^2 dy = ∫[0→2] π y^2 dy = (π * y^3 / 3)|0^2 = (8π/3)? (Note: specific numeric result in lecture was 32π/5 for a different arrangement; always check algebra and limits for each configuration).
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Example 6 (revolving a region about a horizontal line y = 3/2):
- Region between y = x and y = x^3 for x ∈ [0,1], revolve about y = 3/2.
- Outer radius = 3/2 − y_inner? Determine which curve is farther from line:
- Outer radius = |3/2 − x^3| (outer curve measured from axis).
- Inner radius = |3/2 − x|.
- Use washers: V = ∫[0→1] π( [3/2 − x^3]^2 − [3/2 − x]^2 ) dx.
- Simplify algebra first before integrating; combine like terms to reduce work.
Key Problem-Solving Steps (school style)
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- Read the revolving axis and identify whether slices are perpendicular to x or y.
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- Express bounding functions in terms of the variable matching the slicing direction:
- revolve about x-axis or horizontal line → express y = f(x) (use dx).
- revolve about y-axis or vertical line → express x = g(y) (use dy).
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- Find interval of integration by solving intersections or using given bounds.
-
- Decide method:
- Disc (no hole): single radius → A = π [radius]^2.
- Washer (hole): outer radius and inner radius → A = π(R^2 − r^2).
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- Express radii correctly (distance from axis; subtract y-values or x-values appropriately).
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- Simplify integrand algebraically before integrating.
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- Integrate and evaluate definite integral; keep π factor.
Common Mistakes / Tips
- Always match the variable of the function to the axis you rotate around (x for x-axis, y for y-axis).
- Determine which curve gives the outer radius and which gives the inner radius for the entire interval. If curves cross within the interval, split integral at intersection points.
- When revolving about a horizontal line y = k (or vertical line x = k), radii are distances to that line: use |k − y(x)| or |k − x(y)|.
- Simplify algebra (expand and combine like terms) before integrating to reduce errors.
- Pull constants (like π) outside integrals.
- Check signs carefully when evaluating definite integrals; evaluate upper bound first, then subtract lower bound.
Summary Table (Methods and When To Use)
| Method | Cross-Section Shape | General Formula |
|---|
| Discs (about x-axis) | Circle with radius r(x) = f(x) | V = ∫[a→b] π [f(x)]^2 dx |
| Discs (about y-axis) | Circle with radius r(y) = u(y) | V = ∫[c→d] π [u(y)]^2 dy |
| Washers (about x-axis) | Washer; outer radius R(x), inner r(x) | V = ∫[a→b] π ( [R(x)]^2 − [r(x)]^2 ) dx |
| Washers (about y-axis) | Washer; outer radius R(y), inner r(y) | V = ∫[c→d] π ( [R(y)]^2 − [r(y)]^2 ) dy |
Action Items / Next Steps
- Practice problems: set up and evaluate volumes for regions rotated about x-axis, y-axis, and horizontal/vertical lines.
- Practice converting functions: solve y = f(x) for x = g(y) when required.
- Before integrating, always:
- find correct bounds,
- decide outer and inner radii,
- simplify integrand.
- Next lecture preview: cylindrical shells method (useful when discs/washers are awkward); note variable roles swap for shells (revolve about y-axis tends to use x, and revolve about x-axis tends to use y).