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Volumes by Discs and Washers

Dec 24, 2025

Overview

  • Topic: Volumes of solids using the methods of slicing: Discs and Washers.
  • Goal: Use Riemann-sum idea to derive integrals that compute volumes by adding cross-sectional areas.
  • Main methods covered: Volume by slicing (general), Discs (solid of revolution about axis), Washers (hollow solids), and application to rotations about x- and y-axes and about horizontal lines.

Key Concepts

  • Volume by slicing:
    • Cut a solid into thin slabs (slices) perpendicular to an axis.
    • Volume of one slab ≈ (cross-sectional area at xk) * Δx.
    • Sum slabs and take limit as Δx → 0 to get integral: V = ∫[a→b] A(x) dx.
  • Cross-sectional area:
    • For slices perpendicular to x-axis: A(x) is area of cross-section at x.
    • For slices perpendicular to y-axis: A(y) is area of cross-section at y.
  • Discs method (solids of revolution without hole):
    • Cross-section is a circle with radius r(x) = f(x) when revolving y = f(x) about x-axis.
    • Formula: V = ∫[a→b] Ï€ [f(x)]^2 dx.
    • If revolving about y-axis, use functions expressed as x = u(y): V = ∫[c→d] Ï€ [u(y)]^2 dy.
  • Washers method (solids of revolution with hole):
    • Outer radius R(x) from the axis, inner radius r(x) from axis.
    • Cross-sectional area = Ï€[R(x)]^2 − Ï€[r(x)]^2 = Ï€( R^2 − r^2 ).
    • Formula: V = ∫[a→b] Ï€ ( [outer radius]^2 − [inner radius]^2 ) dx (or dy if perpendicular to y).
  • Important setup rules:
    • Discs/Washers: express functions in terms of the variable corresponding to the axis perpendicular to slices (revolve about x-axis → functions in x; revolve about y-axis → functions in y).
    • Identify interval [a,b] by intersection points of bounding curves or given bounds.
    • Determine which curve gives the outer radius (top or right as appropriate) and which gives inner radius (bottom or left).
    • Simplify algebra before integrating.*

Formulas and Definitions

  • Volume by slicing (general): V = ∫[a→b] A(x) dx.
  • Disc method (about x-axis): V = ∫[a→b] Ï€ [f(x)]^2 dx.
  • Disc method (about y-axis): V = ∫[c→d] Ï€ [u(y)]^2 dy.
  • Washer method (about x-axis): V = ∫[a→b] Ï€ ( [F(x)]^2 − [G(x)]^2 ) dx (F outer, G inner).
  • Washer method (about y-axis): V = ∫[c→d] Ï€ ( [U(y)]^2 − [V(y)]^2 ) dy.

When revolving about a horizontal line y = k:

  • Outer radius = distance from line y = k to outer curve = |k − y_outer(x)|.
  • Inner radius = distance from line y = k to inner curve = |k − y_inner(x)|.
  • Then use washers with those radii squared and integrated over x (if slices perpendicular to x).

Worked Example Summaries

  • Example 1 (simple cylinder-like stack):

    • Region: cross-section is a circle of radius 1, x from 1 to 5.
    • A(x) = Ï€(1)^2 = Ï€ → V = ∫[1→5] Ï€ dx = 4Ï€.
    • Matches cylinder volume formula base area * height.
  • Example 2 (disc method, y = 3√x from x=1 to 4, about x-axis):

    • Setup: V = ∫[1→4] Ï€ [3√x]^2 dx = ∫[1→4] 9Ï€ x dx.
    • Integrate: 9Ï€ * (x^2/2)|1^4 = (9Ï€/2)(16 − 1) = (9Ï€/2)*15 = 135Ï€/2.
  • Example 3 (derive sphere volume by discs):

    • Start with upper semicircle: y = √(R^2 − x^2), x ∈ [−R, R], revolve about x-axis.
    • Disc radius = y = √(R^2 − x^2).
    • V = ∫[−R→R] Ï€ (R^2 − x^2) dx.
    • Integrate and simplify to V = (4/3)Ï€ R^3.
  • Example 4 (washer method, region between f(x) and g(x) rotated about x-axis):

    • Given: region between y = f(x) and y = g(x) for x ∈ [a,b]. If f(x) ≥ g(x).
    • V = ∫[a→b] Ï€( f(x)^2 − g(x)^2 ) dx.
    • Worked numeric: region between y = x^2 + 1/4 and y = x^2 for x ∈ [0,2] led to simplified integrand and final numeric volume (including factor Ï€).
  • Example 5 (disc about y-axis using x = u(y)):

    • y = x with y ∈ [0,2], revolve about y-axis.
    • Solve for x in terms of y: x = y.
    • V = ∫[0→2] Ï€ [x(y)]^2 dy = ∫[0→2] Ï€ y^2 dy = (Ï€ * y^3 / 3)|0^2 = (8Ï€/3)? (Note: specific numeric result in lecture was 32Ï€/5 for a different arrangement; always check algebra and limits for each configuration).
  • Example 6 (revolving a region about a horizontal line y = 3/2):

    • Region between y = x and y = x^3 for x ∈ [0,1], revolve about y = 3/2.
    • Outer radius = 3/2 − y_inner? Determine which curve is farther from line:
      • Outer radius = |3/2 − x^3| (outer curve measured from axis).
      • Inner radius = |3/2 − x|.
    • Use washers: V = ∫[0→1] Ï€( [3/2 − x^3]^2 − [3/2 − x]^2 ) dx.
    • Simplify algebra first before integrating; combine like terms to reduce work.

Key Problem-Solving Steps (school style)

    1. Read the revolving axis and identify whether slices are perpendicular to x or y.
    1. Express bounding functions in terms of the variable matching the slicing direction:
    • revolve about x-axis or horizontal line → express y = f(x) (use dx).
    • revolve about y-axis or vertical line → express x = g(y) (use dy).
    1. Find interval of integration by solving intersections or using given bounds.
    1. Decide method:
    • Disc (no hole): single radius → A = Ï€ [radius]^2.
    • Washer (hole): outer radius and inner radius → A = Ï€(R^2 − r^2).
    1. Express radii correctly (distance from axis; subtract y-values or x-values appropriately).
    1. Simplify integrand algebraically before integrating.
    1. Integrate and evaluate definite integral; keep π factor.

Common Mistakes / Tips

  • Always match the variable of the function to the axis you rotate around (x for x-axis, y for y-axis).
  • Determine which curve gives the outer radius and which gives the inner radius for the entire interval. If curves cross within the interval, split integral at intersection points.
  • When revolving about a horizontal line y = k (or vertical line x = k), radii are distances to that line: use |k − y(x)| or |k − x(y)|.
  • Simplify algebra (expand and combine like terms) before integrating to reduce errors.
  • Pull constants (like Ï€) outside integrals.
  • Check signs carefully when evaluating definite integrals; evaluate upper bound first, then subtract lower bound.

Summary Table (Methods and When To Use)

MethodCross-Section ShapeGeneral Formula
Discs (about x-axis)Circle with radius r(x) = f(x)V = ∫[a→b] π [f(x)]^2 dx
Discs (about y-axis)Circle with radius r(y) = u(y)V = ∫[c→d] π [u(y)]^2 dy
Washers (about x-axis)Washer; outer radius R(x), inner r(x)V = ∫[a→b] π ( [R(x)]^2 − [r(x)]^2 ) dx
Washers (about y-axis)Washer; outer radius R(y), inner r(y)V = ∫[c→d] π ( [R(y)]^2 − [r(y)]^2 ) dy

Action Items / Next Steps

  • Practice problems: set up and evaluate volumes for regions rotated about x-axis, y-axis, and horizontal/vertical lines.
  • Practice converting functions: solve y = f(x) for x = g(y) when required.
  • Before integrating, always:
    • find correct bounds,
    • decide outer and inner radii,
    • simplify integrand.
  • Next lecture preview: cylindrical shells method (useful when discs/washers are awkward); note variable roles swap for shells (revolve about y-axis tends to use x, and revolve about x-axis tends to use y).