Overview
This lecture explains thermal strain and thermal stress in solids, focusing on a steel rod and railway rails, and derives and applies key formulas.
Thermal Expansion: Basic Concept
- When temperature of a solid increases, its length increases; when temperature decreases, its length decreases.
- Change in temperature is denoted by T, where T = T₂ − T₁.
- For a bar of original length L, free change in length due to temperature change T is:
- α is the coefficient of linear expansion.
Case 1: Free Expansion of a Steel Rod
- One end of rod fixed, other end free; rod is allowed to expand freely.
- Original length = L; temperature increases from T₁ to T₂ (rise = T).
- Free expansion:
- When a material is allowed to expand freely:
- No thermal stress is developed.
- Only change in length occurs; no internal resistance.
Key Points (Free Expansion)
- Free expansion formula applies whenever no external restraint opposes expansion.
- Under free expansion:
- Thermal strain and thermal stress are considered zero because no load is induced.
Case 2: Restrained Expansion of a Steel Rod
- Steel rod of original length L held between two rigid supports (at A and B).
- Temperature increase T tends to increase length by α T L.
- Supports prevent expansion, so actual extension = 0.
- Concept: “extension prevented” = amount the bar wants to expand but cannot.
Thermal Strain (Restrained Rod)
- Extension prevented = α T L
- Thermal strain, e:
- e = (extension prevented) / (original length)
- e = (α T L) / L = α T
- This is called thermal strain.
- Nature:
- For temperature rise with restraint, this thermal strain is compressive.
Thermal Stress (Restrained Rod)
- From Hooke’s law:
- E = stress / strain = σ / e
- So, σ = E e
- Substituting e = α T:
- This is thermal stress.
- Nature:
- For temperature rise with fixed supports, thermal stress is compressive.
- If temperature decreases and contraction is prevented, thermal stress becomes tensile.
Summary Table: Free vs Restrained Expansion
| Condition | Change in length | Strain | Stress | Nature of stress |
|---|
| Free expansion | ΔL = α T L | 0 (no restraint) | 0 | None |
| Restrained, ΔT > 0 | 0 (expansion prevented) | e = α T | σ = E α T | Compressive thermal |
| Restrained, ΔT < 0 | 0 (contraction prevented) | e = α T (sign wise) | σ = E α T | Tensile thermal |
Important Thermal Formulas (Rod Under Restraint)
- Free expansion:
- Thermal strain (when expansion/contraction is fully prevented):
- Thermal stress (full restraint):
These three formulas are used for many objective and conventional problems in thermal stress and strain.
Numerical Problem: Steel Railway Rails
Given (for all parts unless changed in part statement):
- Material: Steel rails
- Initial temperature: T₁ = 24 °C
- Length of each rail: L = 32 m
- Coefficient of linear expansion: α = 11 × 10⁻⁶ per °C
- Young’s modulus: E = 205 GPa = 205 × 10⁹ Pa
Part 1: Stress at 80 °C with No Allowance for Expansion
- Final temperature: T₂ = 80 °C
- Temperature rise:
- T = T₂ − T₁ = 80 − 24 = 56 °C
- Rails are laid with no gap; no allowance for expansion.
- So expansion is completely prevented → full thermal stress develops.
- Formula:
- σ = E α T
- σ = (205 × 10⁹) × (11 × 10⁻⁶) × 56
- Calculated result:
- σ ≈ 12.628 × 10⁶ Pa ≈ 12.63 MPa
- (Lecturer writes 12 6.28 × 10⁶ Pa and quotes ≈ 12.6 MPa type magnitude)
- Nature:
- Thermal stress is compressive because the rails try to expand but are restrained.
Part 2: Stress at 80 °C with 8 mm Expansion Allowance
- There are two rails with a gap between their ends:
- Expansion allowance (gap) = 8 mm
- Each rail length: 32 m
- Temperature rise: still T = 56 °C
- The rail can first expand into the 8 mm gap without any stress.
- Only the remaining portion of free expansion is prevented, which causes stress.
Thermal Strain with Partial Allowance
- Free expansion that would occur without restraint:
- Actual “expansion prevented”:
- Thermal strain:
- e = (expansion prevented) / L
- e = (α T L − 8) / L
- Using Hooke’s law:
- e = σ / E
- So, σ / E = (α T L − 8) / L
Substitution
Part 3: Expansion Allowance for No Stress at 80 °C
- Aim: find expansion allowance (ΔL) so that no stress develops at 80 °C.
- Condition for no thermal stress:
- Rail must be allowed to expand freely by the full free expansion amount.
- Free expansion:
- Substitute:
- ΔL = (11 × 10⁻⁶) × 56 × 32
- ΔL ≈ 0.01971 m
- Convert to mm:
- Interpretation:
- If an allowance of about 19.71 mm is provided and temperature rises from 24 °C to 80 °C,
- then rails can expand without restraint and no thermal stress will be generated.
Part 4: Maximum Temperature for No Stress with 8 mm Allowance
- Given:
- Expansion allowance: ΔL = 8 mm = 8 × 10⁻³ m
- Length L = 32 m
- α = 11 × 10⁻⁶ per °C
- Initial temperature: T₁ = 24 °C
- Condition for no stress:
- Allowance exactly equals free expansion: ΔL = α T L
- Free expansion relation:
- 8 × 10⁻³ = α (T₂ − T₁) L
- 8 × 10⁻³ = (11 × 10⁻⁶) (T₂ − 24) (32)
- Solve for T₂:
- Rise in temperature allowed without stress:
- T = T₂ − T₁ ≈ 46.72 − 24 ≈ 22.72 °C
Numerical Results Summary
| Part | Condition | Given / Found | Key formula | Result |
|---|
| 1 | No allowance, T from 24 °C to 80 °C | α = 11×10⁻⁶, E = 205 GPa, T = 56 °C | σ = E α T | σ ≈ 12.6 MPa (compressive) |
| 2 | Allowance = 8 mm, T from 24 °C to 80 °C | Gap = 8 mm, length = 32 m | σ / E = (αTL − 8)/L | σ ≈ 75.3 MPa |
| 3 | Find allowance for no stress at 80 °C | T = 56 °C, length = 32 m | ΔL = α T L | ΔL ≈ 19.71 mm |
| 4 | Allowance = 8 mm, find max T for zero stress | ΔL = 8 mm, length = 32 m, α = 11×10⁻⁶ per °C, T₁ = 24 °C | ΔL = α (T₂ − T₁) L | T₂ ≈ 46.72 °C, ΔT ≈ 22.72 °C |
Practical Insight: Railway Track Gaps
- Rails are joined with plates and bolts; a small gap is intentionally left between rail ends.
- This gap is the expansion allowance to:
- Let rails expand in hot weather.
- Reduce thermal stresses to safe levels.
- Without gaps (allowance), high compressive thermal stresses can develop, leading to track buckling.
Key Terms & Definitions
- Thermal expansion: Increase in length or volume of a material due to temperature rise.
- Coefficient of linear expansion (α):
- Constant relating change in length to temperature change for a given material.
- Free expansion: Expansion when a body is not restrained; no stress develops.
- Thermal strain (e):
- Strain in a body due to temperature change when expansion or contraction is prevented.
- For full restraint: e = α T.
- Thermal stress (σ):
- Stress induced due to prevention of thermal expansion or contraction.
- For full restraint: σ = E α T.
- Compressive thermal stress:
- Stress produced when expansion is prevented during temperature rise.
- Tensile thermal stress:
- Stress produced when contraction is prevented during temperature decrease.
- Expansion allowance:
- Intentional gap provided to permit some thermal expansion without developing stress.
Action Items / Next Steps
- Memorize and practice using:
- ΔL = α T L
- e = α T
- σ = E α T
- Practice similar numericals involving:
- Different materials and lengths.
- Various expansion allowances and temperature ranges.
- Prepare for next lecture on:
- Composite or compound bars consisting of two or more materials.
- Thermal stresses in such combined systems.