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ME 10 Profit Maximization and Marginal Analysis

Jul 3, 2024

Lecture Notes

Differentiation and Initial Equations

  • Differentiating an expression:
    • Start with (3Q^2/3 - 40Q + 102)
    • Simplifies to (Q^2 - 40Q + 102)

MR = MC

  • Set Marginal Revenue (MR) equal to Marginal Cost (MC)
  • Given: MR = 66
  • Equation: (Q^2 - 40Q + 102)

Simplifying the Equation

  • Corrected initial differentiation error by using 10 instead of 20 for simplicity
  • Differentiated expression: (Q^2 - 20Q + 2)
  • Setting MR = MC with simplified values:
    • MR: 66
    • MC: (Q^2 - 20Q + 2) rewritten as ((Q - 10)^2 + 2)
    • 66 can be rewritten as 64 + 2

Solving the Quadratic Equation

  • From ((Q - 10)^2 = ±64):
    • Solutions: (Q = 18) and (Q = 2)
  • Graph representing MR and MC intersection at two points (MC = Q² - 20Q + 2 intersecting MR = 66)

Determining Optimal Production Level

  • Compare MR and MC at different quantities:
    • At Q = 2:
      • Moving from 2 to 3: MC < 66 (MR), leading to profit
      • Moving from 2 to 1: MC > 66 (MR), causing losses
      • Conclusion: Q = 2 is not optimal
    • At Q = 18:
      • Moving from 18 to 19: MC > 66 (MR), causing losses
      • Moving from 18 to 17: Losing profit opportunity
      • Conclusion: Q = 18 is optimal

Key Concepts

  • Profit Maximization: Achieved where MR = MC
  • Margin: In economics, decisions are evaluated marginally for optimization
  • Optimality Criteria: Always relates to the margin

Conclusion: Optimal quantity for production and profit maximization is at Q = 18.

Next Steps

  • Future discussions will continue to involve margin-based optimality criteria

End of lecture for this video.