Lecture Notes
Differentiation and Initial Equations
- Differentiating an expression:
- Start with (3Q^2/3 - 40Q + 102)
- Simplifies to (Q^2 - 40Q + 102)
MR = MC
- Set Marginal Revenue (MR) equal to Marginal Cost (MC)
- Given: MR = 66
- Equation: (Q^2 - 40Q + 102)
Simplifying the Equation
- Corrected initial differentiation error by using 10 instead of 20 for simplicity
- Differentiated expression: (Q^2 - 20Q + 2)
- Setting MR = MC with simplified values:
- MR: 66
- MC: (Q^2 - 20Q + 2) rewritten as ((Q - 10)^2 + 2)
- 66 can be rewritten as 64 + 2
Solving the Quadratic Equation
- From ((Q - 10)^2 = ±64):
- Solutions: (Q = 18) and (Q = 2)
- Graph representing MR and MC intersection at two points (MC = Q² - 20Q + 2 intersecting MR = 66)
Determining Optimal Production Level
- Compare MR and MC at different quantities:
- At Q = 2:
- Moving from 2 to 3: MC < 66 (MR), leading to profit
- Moving from 2 to 1: MC > 66 (MR), causing losses
- Conclusion: Q = 2 is not optimal
- At Q = 18:
- Moving from 18 to 19: MC > 66 (MR), causing losses
- Moving from 18 to 17: Losing profit opportunity
- Conclusion: Q = 18 is optimal
Key Concepts
- Profit Maximization: Achieved where MR = MC
- Margin: In economics, decisions are evaluated marginally for optimization
- Optimality Criteria: Always relates to the margin
Conclusion: Optimal quantity for production and profit maximization is at Q = 18.
Next Steps
- Future discussions will continue to involve margin-based optimality criteria
End of lecture for this video.