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Deriving an Exponential Function
Sep 23, 2024
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Review flashcards
Finding an Exponential Function Through Two Points
Introduction
Objective: Find an exponential function going through two given points (2, 6) and (5, 48).
Model form: ( y = a \cdot b^x )
Setting Up the Equations
Point Substitution:
For point (2, 6):
Equation: ( 6 = a \cdot b^2 )
For point (5, 48):
Equation: ( 48 = a \cdot b^5 )
Aligning Equations:
Write equations on top of each other for easier manipulation.
Solving for ( b )
Elimination by Division:
Divide both sides:
( \frac{6}{48} = \frac{a \cdot b^2}{a \cdot b^5} )
Simplifies to: ( \frac{1}{8} = b^{-3} )
Solving for ( b ):
Raise both sides to (-1/3) to solve for ( b ):
( 8^{1/3} = 2 ), so ( b = 2 )
Solving for ( a )
Substitute & Solve:
Use any point, e.g., (2, 6):
Plug into model: ( 6 = a \cdot 2^2 )
Simplify: ( 6 = 4a )
Solve: ( a = \frac{6}{4} = \frac{3}{2} )
Final Exponential Model
Equation:
( y = \frac{3}{2} \cdot 2^x )
Verification:
Check using exponential regression or graphing to ensure it passes through both points.
Conclusion
The exponential function ( y = \frac{3}{2} \cdot 2^x ) successfully models the data points provided.
Process involved setting up equations, dividing to eliminate variables, and solving for unknowns ( a ) and ( b ).
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