Deriving an Exponential Function

Sep 23, 2024

Finding an Exponential Function Through Two Points

Introduction

  • Objective: Find an exponential function going through two given points (2, 6) and (5, 48).
  • Model form: ( y = a \cdot b^x )

Setting Up the Equations

  1. Point Substitution:
    • For point (2, 6):
      • Equation: ( 6 = a \cdot b^2 )
    • For point (5, 48):
      • Equation: ( 48 = a \cdot b^5 )
  2. Aligning Equations:
    • Write equations on top of each other for easier manipulation.

Solving for ( b )

  1. Elimination by Division:
    • Divide both sides:
      • ( \frac{6}{48} = \frac{a \cdot b^2}{a \cdot b^5} )
    • Simplifies to: ( \frac{1}{8} = b^{-3} )
  2. Solving for ( b ):
    • Raise both sides to (-1/3) to solve for ( b ):
    • ( 8^{1/3} = 2 ), so ( b = 2 )

Solving for ( a )

  1. Substitute & Solve:
    • Use any point, e.g., (2, 6):
    • Plug into model: ( 6 = a \cdot 2^2 )
    • Simplify: ( 6 = 4a )
    • Solve: ( a = \frac{6}{4} = \frac{3}{2} )

Final Exponential Model

  • Equation: ( y = \frac{3}{2} \cdot 2^x )
  • Verification:
    • Check using exponential regression or graphing to ensure it passes through both points.

Conclusion

  • The exponential function ( y = \frac{3}{2} \cdot 2^x ) successfully models the data points provided.
  • Process involved setting up equations, dividing to eliminate variables, and solving for unknowns ( a ) and ( b ).