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Nth-Term Rules and Sequence Types

Nov 29, 2025

Overview

These notes cover sequences defined by an nth-term formula, how to find terms, how to decide if a number is in a sequence, and how to find the nth-term rule from given terms, including special sequences (Fibonacci and geometric).

Using an nth-term rule to find terms

  • The nth-term (position-to-term rule) gives the value of the term at position n in the sequence.
  • To find specific terms, substitute n = 1, 2, 3, … into the nth-term expression.

Example: nth-term 5n + 1

  • First term: n = 1 β†’ 5(1) + 1 = 6
  • Second term: n = 2 β†’ 5(2) + 1 = 11
  • Third term: n = 3 β†’ 5(3) + 1 = 16
  • 100th term: n = 100 β†’ 5(100) + 1 = 501

Example: nth-term 9n βˆ’ 3

  • First term: n = 1 β†’ 9(1) βˆ’ 3 = 6
  • Second term: n = 2 β†’ 9(2) βˆ’ 3 = 15
  • Third term: n = 3 β†’ 9(3) βˆ’ 3 = 24

Example: nth-term 9n βˆ’ 2 (first five terms)

  • T₁: n = 1 β†’ 9(1) βˆ’ 2 = 7
  • Tβ‚‚: n = 2 β†’ 9(2) βˆ’ 2 = 16
  • T₃: n = 3 β†’ 9(3) βˆ’ 2 = 25
  • Tβ‚„: add 9 β†’ 25 + 9 = 34
  • Tβ‚…: add 9 β†’ 34 + 9 = 43 (check: 9(5) βˆ’ 2 = 43)

Summary table: evaluating nth-term rules

Nth-term rulenTerm value
5n + 116
211
316
9n βˆ’ 316
215
324
9n βˆ’ 217
216
325
434
543

Testing whether a number is in a sequence

  • Idea: If a number T is a term, there exists a whole number n such that nth-term expression = T.
  • Solve the equation and check whether n is a whole number (positive integer).

Example: nth-term 3n βˆ’ 5; is 95 in the sequence?

  • Solve 3n βˆ’ 5 = 95
    • Add 5: 3n = 100
    • Divide by 3: n = 100/3 = 33.\overline{3}
  • n is not a whole number, so 95 is not in the sequence.
  • Check nearby terms:
    • 33rd term: 3(33) βˆ’ 5 = 99 βˆ’ 5 = 94
    • 34th term: 3(34) βˆ’ 5 = 102 βˆ’ 5 = 97
    • 95 lies between 94 and 97, so it is not a term.

Example: nth-term 4n + 1; is 37 in the sequence?

  • Solve 4n + 1 = 37
    • Subtract 1: 4n = 36
    • Divide by 4: n = 9
  • n is a whole number, so 37 is a term; it is the 9th term.

Example: nth-term 9n βˆ’ 2; is 80 in the sequence?

  • Solve 9n βˆ’ 2 = 80
    • Add 2: 9n = 82
    • Divide by 9: n = 82/9
  • 82 is not in the 9 times table; n is not a whole number.
  • 9 Γ— 9 = 81, so 82/9 = 9 and 1/9.
  • 80 is not in the sequence; it lies between the 9th and 10th terms.

Summary table: checking membership

Nth-term ruleTarget valueEquationnIn sequence?Notes
3n βˆ’ 5953n βˆ’ 5 = 95100/3NoBetween 33rd (94) and 34th (97)
4n + 1374n + 1 = 379Yes9th term
9n βˆ’ 2809n βˆ’ 2 = 8082/9NoBetween 9th and 10th terms

Finding an nth-term rule from a sequence

General method for linear sequences (constant difference):

  1. Find the term-to-term difference (d).
  2. Write dn as the basic part (d times table).
  3. Compare dn with the given sequence to find the constant adjustment (add or subtract a fixed number).
  4. Write nth-term as dn Β± constant.

Example: 7, 11, 15, 19, 23

  • Differences: +4 each time β†’ starts with 4n (4 times table).
  • 4 times table: 4, 8, 12, 16, 20.
  • Compare: sequence = times table + 3 each time.
  • nth-term: 4n + 3.

Example: 4, 10, 16, 22, 28

  • Differences: +6 each time β†’ starts with 6n (6 times table).
  • 6 times table: 6, 12, 18, 24, 30.
  • Sequence is always 2 less than 6n.
  • nth-term: 6n βˆ’ 2.

Example: decreasing sequence with difference βˆ’5

  • Sequence goes down by 5 each time β†’ use βˆ’5n (negative 5 times table).
  • βˆ’5 times table: βˆ’5, βˆ’10, βˆ’15, …
  • To match the given sequence, we must add 29 to βˆ’5n.
  • nth-term: βˆ’5n + 29 (or 29 βˆ’ 5n).

Example: decreasing sequence with difference βˆ’3

  • Sequence goes down by 3 each time β†’ use βˆ’3n (negative 3 times table).
  • βˆ’3 times table: βˆ’3, βˆ’6, βˆ’9, βˆ’12, βˆ’15.
  • We must add 35 to βˆ’3n to get the given terms.
  • nth-term: βˆ’3n + 35.

Example: 5, 12, 19, 26, 33

  • Differences: +7 each time β†’ start with 7n.
  • 7 times table: 7, 14, 21, 28, 35.
  • Sequence is 2 less than 7n each time.
  • nth-term: 7n βˆ’ 2.

Summary table: forming nth-term rules

SequenceDifferenceBase tableAdjustmentNth-term rule
7, 11, 15, 19, 23+44n+34n + 3
4, 10, 16, 22, 28+66nβˆ’26n βˆ’ 2
(down by 5 each term)βˆ’5βˆ’5n+29βˆ’5n + 29
(down by 3 each term)βˆ’3βˆ’3n+35βˆ’3n + 35
5, 12, 19, 26, 33+77nβˆ’27n βˆ’ 2

Special sequences: Fibonacci and geometric

Fibonacci sequence

  • Rule: each term (from the third onwards) is the sum of the previous two terms.
  • Example given (first six terms shown; starts 1, 2, 3, 5, 8, 13 pattern implied by explanation):
    • 1st + 2nd β†’ 3rd
    • 2nd + 3rd β†’ 4th
    • 3rd + 4th β†’ 5th
    • 4th + 5th β†’ 6th
  • Finding next terms:
    • 5th term = 3, 6th term = 5 β†’ 7th term = 3 + 5 = 8
    • 8th term = 5 + 8 = 13
  • Could continue: next would be 8 + 13 = 21, then 13 + 21, etc.

Geometric sequence (multiplicative pattern)

  • Rule: multiply by the same number each time to get the next term.
  • Example: doubling sequence
    • Each term is 2 Γ— previous term.
    • Next term after 48: 2 Γ— 48 = 96
    • Next term after 96: 2 Γ— 96 = 192

Summary table: special sequences

TypeRuleExample stepNext terms shown
FibonacciNext term = sum of previous two terms3, 5 β†’ 8; 5, 8 β†’ 138, 13 (then 21, …)
GeometricNext term = previous term Γ— constant multiplierMultiply by 2: 48 β†’ 96 β†’ …96, 192

Key Terms & Definitions

  • nth-term: An expression that gives the term at position n in a sequence.
  • Position-to-term rule: Another name for the nth-term rule.
  • Term-to-term rule: The rule that describes how to get from one term to the next (e.g. β€œadd 4”, β€œmultiply by 2”).
  • Linear sequence: A sequence with a constant difference between terms (e.g. +4 each time).
  • Geometric sequence: A sequence where each term is obtained by multiplying the previous term by a fixed number.
  • Fibonacci sequence: A sequence where each term is the sum of the previous two terms.
  • Whole number (for n): Positive integer index (1, 2, 3, …); required for a value to be a valid term position.

Action Items / Next Steps

  • Practise finding first several terms for given nth-term formulas by substitution.
  • Practise testing whether a given number is in a sequence by solving an equation for n.
  • Practise deriving nth-term rules: find the difference, form dn, then determine and apply the constant adjustment.
  • Learn to recognise Fibonacci and geometric sequences from their defining patterns.