May 22, 2024
x, y and hypotenuse rθx^2 + y^2 = r^2x = r cos(θ)y = r sin(θ)tan(θ) = y / xr or θ (e.g., r = 5 sin(θ), r = 7)x and y (e.g., x^2 + y^2 = 4, x = 3, x^2 = 4y)r = 7r^2 = 7^2 = 49x^2 + y^2 = r^2x^2 + y^2 = 49r = 5r^2 = 25x^2 + y^2 = 25x^2 + y^2 = 25θ = π/4tan(θ) = tan(π/4)tan(θ) = y/x, tan(π/4) = 1x: y = xθ = 0°tan(θ) = tan(0°)tan(0°) = 0, so y/x = 0y = 0θ = π/2tan(θ) = tan(π/2)tan(π/2) is undefined, so x = 0x = 0r sin(θ) = 5, r cos(θ) = 4r sin(θ) = y, so y = 5r cos(θ) = x, so x = 4r = 3 csc(θ)csc(θ) = 1/sin(θ)r sin(θ) = 3y = 3r = 4 sec(θ)sec(θ) = 1/cos(θ)r cos(θ) = 4x = 4r = 3 sin(θ)r: r^2 = 3r sin(θ)x^2 + y^2 = r^2, y = r sin(θ)x^2 + y^2 = 3yr = 4 cos(θ)r: r^2 = 4r cos(θ)x^2 + y^2 = r^2, x = r cos(θ)x^2 + y^2 = 4xr = 3 cos(θ) + 5 sin(θ)r: r^2 = 3r cos(θ) + 5r sin(θ)x^2 + y^2 = r^2, x = r cos(θ), y = r sin(θ)x^2 + y^2 = 3x + 5yr = 5 / (2 cos(θ) + 3 sin(θ))r(2 cos(θ) + 3 sin(θ)) = 5r: 2r cos(θ) + 3r sin(θ) = 5x = r cos(θ), y = r sin(θ)2x + 3y = 5r^2 sin(2θ) = 8sin(2θ) = 2 sin(θ) cos(θ)r^2 2 sin(θ) cos(θ) = 8r^2 sin(θ) cos(θ) = 4xy = 4 -> y = 4/xr = 8 / cos(θ)cos(θ): r cos(θ) = 8x = 8r = 5 cos(θ) / sin^2(θ)sin(θ): r sin(θ) = 5 cos(θ)/sin(θ)y = 5 cot(θ)cot(θ) = x/yy^2 = 5xr = sin(θ) cos^2(θ)r^3: r^4 = r^3 sin(θ) cos^2(θ)x^2 + y^2 = x sqrt(y)