Overview
These notes explain how to balance chemical equations using coefficients, with worked examples and special tips for polyatomic ions.
Basic Rules for Balancing Equations
- Atoms are neither created nor destroyed, so each element must have equal atoms on both sides.
- You may only change coefficients (numbers in front of formulas), never subscripts (small numbers in formulas).
- If no subscript is written after an element symbol, it is assumed to be 1.
- If no coefficient is written in front of a formula, it is assumed to be 1.
- Always recount atoms after changing any coefficient, because changes affect all atoms in that formula.
General Step-by-Step Method
- Step 1: Count atoms of each element on both sides of the equation.
- Step 2: Compare counts and identify which elements are unbalanced.
- Step 3: Change coefficients to make atom counts equal for each element.
- Step 4: Recount atoms; repeat adjustments until all elements are balanced.
- Step 5: Check that no subscripts have been changed and that all coefficients are in the simplest whole-number ratio.
Worked Example 1: Simple Sulfur–Oxygen Equation
- Start: Left side has 8 sulfur atoms and 2 oxygen atoms.
- Right side has 1 sulfur atom and 2 oxygen atoms.
- Oxygen is already balanced (2 on each side); sulfur is not (8 vs. 1).
- Put coefficient 8 in front of sulfur on the product side.
- This gives 8 sulfur atoms on the right, but now also 16 oxygens on the right.
- To fix oxygen, put coefficient 8 in front of the oxygen-containing reactant with 2 oxygens.
- Now left side has 8 sulfurs and 16 oxygens; right side has 8 sulfurs and 16 oxygens.
- The equation is now balanced using only coefficients.
Worked Example 2: Hydrogen and Oxygen Equation
- Initial counts: Left has 2 hydrogens and 2 oxygens.
- Right has 2 hydrogens and 1 oxygen.
- To balance oxygen, place coefficient 2 in front of the oxygen-containing product.
- Now right side has 2 oxygens but 4 hydrogens.
- To balance hydrogen, place coefficient 2 in front of the hydrogen-containing reactant.
- Now each side has 4 hydrogens and 2 oxygens.
- The equation is balanced.
Worked Example 3: Polyatomic Ions Treated as a Unit
- Some equations contain the same polyatomic ion on both sides (examples: SO₄, NO₃).
- When a polyatomic ion appears unchanged on both sides, you can count it as one “chunk.”
- Example counts:
- Calcium: 1 on left, 1 on right.
- SO₄ group: 1 on left, 1 on right (treated as one unit).
- Na: 2 on left.
- NO₃: 1 on left; on the right, a subscript 2 outside parentheses gives 2 NO₃ groups.
- To balance sodium and nitrate:
- Put coefficient 2 in front of the sodium–nitrate compound on the product side.
- Na: 1 × 2 = 2 on the right, matching left.
- NO₃: 1 × 2 = 2 on the right, matching the 2 NO₃ groups.
- All species are now balanced.
- Treating polyatomic ions as one item simplifies counting and balancing.
Polyatomic Ion Balancing Summary Table
| Species | Left Side Count | Right Side Count (before) | Right Side Coefficient Used | Right Side Count (after) |
|---|
| Ca | 1 | 1 | 2 | 1 × 2 = 2 (if in that term) |
| SO₄ | 1 | 1 | 2 | 1 × 2 = 2 (if in that term) |
| Na | 2 | 1 | 2 | 1 × 2 = 2 |
| NO₃ | 1 | 2 (due to subscript 2) | 2 | 2 × 1 = 2 or matched value |
(Counts reflect the logic described: ions on both sides, coefficient effect, and subscripts outside parentheses.)
Worked Example 4: Combustion-Type Equation with Multiple Oxygens
- Initial counts on left: 1 carbon, 4 hydrogens, 2 oxygens.
- Initial counts on right:
- 1 carbon in CO₂.
- 2 oxygens in CO₂.
- 2 hydrogens in H₂O.
- Plus 1 more oxygen from another oxygen-containing reactant or product, total 3 oxygens on that side.
- Start by balancing hydrogen:
- Put coefficient 2 in front of H₂O (or hydrogen-containing product).
- Now right side has 2 × 2 = 4 hydrogens, matching left.
- Recount oxygens on the right:
- 2 oxygens from CO₂.
- Plus 2 × 1 oxygen from water gives 2 more oxygens.
- Total oxygens on right = 4.
- To balance oxygens, put coefficient 2 in front of the O₂ (or oxygen-containing reactant with 2 oxygens) on the left.
- Now left side has 2 × 2 = 4 oxygens, matching the 4 oxygens on the right.
- Carbons and hydrogens remain balanced; the equation is balanced.
Key Terms & Definitions
- Coefficient: Number written in front of a chemical formula; multiplies all atoms in that formula.
- Subscript: Small number written after an element symbol inside a formula; gives number of atoms of that element.
- Reactants: Substances present on the left side of the equation; they undergo change.
- Products: Substances present on the right side of the equation; they are formed in the reaction.
- Polyatomic ion: Group of atoms that acts as a single charged unit and appears unchanged on both sides of some equations.
Action Items / Next Steps
- Practice counting atoms carefully, including atoms in polyatomic ions and atoms repeated in different products.
- Work additional balancing problems, increasing difficulty to gain speed and confidence.
- Always double-check atom counts for every element after setting final coefficients.