Jul 11, 2024
x = 1 + 6t
for t
in [0, 1]
.y = 2 - 8t
for t
in [0, 1]
.z = 3 + 2t
for t
in [0, 1]
.t = 0
: starting point (1, 2, 3).t = 1
: ending point (7, -6, 5).t
.x = t
.y = t² + 1
.t
ranging from 1 to 3.x = 1
to x = 3
.x = 3cos(t)
, y = 3sin(t)
.t
in [π/2, π].t
in [0, 1]
.
x = 1 + 6t
, y = 2 - 8t
, z = 3 + 2t
.t
in [0, 2]
.
x = 1 + 3t
, y = 2 - 4t
, z = 3 + t
.