17.1 General Physics: Current and Ohm's Law

Jul 15, 2024

General Physics: Current and Ohm's Law

Introduction

  • Presenter: Chad from Chad's Prep
  • Topics Covered:
    • Electrical current
    • Ohm's Law
    • Power dissipation across resistors
    • Resistivity
    • Temperature dependence of resistance

Electrical Current

  • Definition: Flow of charge, symbolized by I
  • Mathematical Definition: Change in charge over time
    • I = ΔQ / Δt
  • SI Unit: Ampere (A)
    • 1 A = 1 C/s
  • Conventional Current: Imaginary flow of positive charges, even though actual current is the flow of electrons

Ohm's Law

  • Formula: ΔV = I * R
    • ΔV: Potential difference (Volts)
    • I: Current (Amperes)
    • R: Resistance (Ohms)
  • Resistance (R):
    • R = ΔV / I
    • SI Unit: Ohm (Ω)
  • Current Calculation: I = ΔV / R
    • Directly proportional to ΔV
    • Inversely proportional to R
  • Applications:
    • Resistors in electrical appliances (e.g., light bulbs, toasters)
    • Functions to convert electrical energy into other forms of energy (heat, light)*

Power Dissipation

  • Formula: P = ΔV * I
    • SI Unit: Watt (W) or Joules per second (J/s)
  • Alternate Formulas:
    • P = I^2 * R
    • P = ΔV^2 / R
  • Important Note: Use ΔV across the specific resistor, not necessarily the EMF source
  • Example Problem:
    • Given: I = 3.0 A, R = 2.0 Ω
    • Calculation: ΔV = I * R = 6.0 V, P = ΔV * I = 18 W

Resistivity and Resistance

  • Resistivity (ρ): Characteristic of a material
  • Formula: R = ρ * (L/A)
    • L: Length of the wire
    • A: Cross-sectional area
  • Relationships:
    • R is directly proportional to L
    • R is inversely proportional to A
  • Example Problem:
    • Given: Initial R = 8.00 Ω, new wire 3x length, double radius
    • Calculation: R_new = 3/4 * 8.00 Ω = 6.00 Ω

Temperature Dependence of Resistivity

  • Formula: ρ = ρ_0 * [1 + α * (T - T_0)]
    • ρ_0: Initial resistivity
    • α: Temperature coefficient
    • T: Final temperature
  • Direct Proportionality: R and ρ
  • Example Problem:
    • Given: R = 8.00 Ω at 20.0°C, α = 0.00393 per °C, find R at 50.0°C
    • Calculation: R_new = 8.00 * [1 + 0.00393 * (50.0 - 20.0)] = 8.94 Ω

Superconductors

  • Properties: Zero resistance at low temperatures
  • Current Limitation: Not practical at ambient temperatures
  • Potential Benefits: Increased efficiency in power transmission (e.g., power lines)

Conclusion

  • Encouragement to support and engage with Chad's Prep resources
  • Happy studying!