Jul 15, 2024
II = ΔQ / Δt1 A = 1 C/sΔV = I * R
ΔV: Potential difference (Volts)I: Current (Amperes)R: Resistance (Ohms)R):
R = ΔV / IΩ)I = ΔV / R
ΔVRP = ΔV * I
P = I^2 * RP = ΔV^2 / RΔV across the specific resistor, not necessarily the EMF sourceI = 3.0 A, R = 2.0 ΩΔV = I * R = 6.0 V, P = ΔV * I = 18 Wρ): Characteristic of a materialR = ρ * (L/A)
L: Length of the wireA: Cross-sectional areaR is directly proportional to LR is inversely proportional to AInitial R = 8.00 Ω, new wire 3x length, double radiusR_new = 3/4 * 8.00 Ω = 6.00 Ωρ = ρ_0 * [1 + α * (T - T_0)]
ρ_0: Initial resistivityα: Temperature coefficientT: Final temperatureR and ρR = 8.00 Ω at 20.0°C, α = 0.00393 per °C, find R at 50.0°CR_new = 8.00 * [1 + 0.00393 * (50.0 - 20.0)] = 8.94 Ω