Understanding Two Lens Systems in Optics

Aug 14, 2024

Two Lens System in Physics

Overview

  • A problem involving a two-lens system can seem intimidating but can be simplified using the thin lens formula.
  • The main idea: First, the first lens creates an image of the object, which then acts as an object for the second lens. The second lens creates the final image.
  • Key question: What image does our eye see through these two lenses?

Step-by-Step Approach

Calculation with the First Lens

  • Lens Type: Convex
    • Focal length, ( f_1 ) = +12 cm (positive because it's convex)
  • Object Distance:
    • Measure from the center of the lens to the object.
    • Given: 24 cm + 12 cm = 36 cm
  • Image Distance Calculation:
    • Thin lens formula: ( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} )
      • ( \frac{1}{12} = \frac{1}{36} + \frac{1}{d_i} )
    • Solve for ( d_i ): ( d_i = 18 ) cm (positive, on the same side as the eye)
    • The image formed by the first lens is 18 cm from the lens center.

Calculation with the Second Lens

  • Image from First Lens as Object for Second Lens:
    • Distance from the lens to the image: 33 cm (total) - 18 cm = 15 cm
  • Lens Type: Diverging
    • Focal length, ( f_2 ) = -10 cm (negative because it's diverging)
  • Image Distance Calculation:
    • Thin lens formula: ( \frac{1}{-10} = \frac{1}{15} + \frac{1}{d_i} )
    • Solve for ( d_i ): ( d_i = -6 ) cm (negative, on the same side as the eye)

Final Image Position

  • The final image is 6 cm to the left of the second lens center.

Magnification Calculations

First Lens Magnification

  • Formula: ( M_1 = \frac{-d_i}{d_o} )
    • ( M_1 = \frac{-18}{36} = -\frac{1}{2} )
    • Image is 1/2 the size of the object and inverted.

Second Lens Magnification

  • Formula: ( M_2 = \frac{-d_i}{d_o} )
    • ( M_2 = \frac{-(-6)}{15} = \frac{2}{5} )
    • Image is 2/5 the size of the first image and maintains orientation (still inverted).

Total Magnification

  • Combined magnification: ( M_{total} = M_1 \times M_2 )
    • ( M_{total} = -\frac{1}{2} \times \frac{2}{5} = -\frac{1}{5} )
    • Final image is 1/5 the size of the original object and inverted.

Key Takeaways

  • Treat each lens separately using the thin lens formula.
  • Use magnification formulas to determine image size and orientation.
  • Overall magnification is the product of individual magnifications.
  • The thin lens formula provides image position; magnification gives size and orientation.
  • An understanding of this setup is crucial for applications like microscopes.