📏

Equations of Parallel and Perpendicular Lines

May 6, 2025

Writing Equations of Lines: Parallel and Perpendicular

Introduction

  • Focus on writing equations of lines that are parallel or perpendicular to a given line.
  • Use the point-slope form and slope-intercept form.

Parallel Lines

  • Key Concept: Parallel lines have the same slope.

  • Example 1: Given the line $y = 2x + 1$, write the equation of a line parallel to it passing through (1, 5).

    • Slope (m) is 2.
    • Use the slope-intercept form: $y = mx + b$.
    • Substitute $x = 1$, $y = 5$: $5 = 2(1) + b \Rightarrow b = 3$.
    • Equation: $y = 2x + 3$.
  • Example 2: Given $y = 3x - 4$, find the parallel line through (6, 4).

    • Slope (m) is 3.
    • Substitute $x = 6$, $y = 4$: $4 = 3(6) + b \Rightarrow b = -14$.
    • Equation: $y = 3x - 14$.

Using Point-Slope Form

  • Example 3: Line $y = \frac{3}{2}x + 3$, point (4, -3).
    • Slope (m) is $\frac{3}{2}$.
    • Point-slope form: $y - y_1 = m(x - x_1)$.
    • Substitute $x_1 = 4$, $y_1 = -3$: $y + 3 = \frac{3}{2}(x - 4)$.
    • Distribute: $y + 3 = \frac{3}{2}x - 6$.
    • Convert to slope-intercept: $y = \frac{3}{2}x - 9$.

Perpendicular Lines

  • Key Concept: Perpendicular lines have slopes that are negative reciprocals.

  • Example 4: Given $y = 5x - 3$, find the perpendicular line through (2, 1).

    • Original slope is 5.
    • Perpendicular slope: $-\frac{1}{5}$.
    • Point-slope form: $y - y_1 = m(x - x_1)$.
    • Substitute $x_1 = 2$, $y_1 = 1$: $y - 1 = -\frac{1}{5}(x - 2)$.
    • Distribute: $y = -\frac{1}{5}x + \frac{7}{5}$.
  • Example 5: Given $y = \frac{3}{4}x - 1$, perpendicular line through (8, -3).

    • Perpendicular slope: $-\frac{4}{3}$.
    • Substitute $x = 8$, $y = -3$: $-3 = -\frac{4}{3}(8) + b$.
    • Solve for $b$: $b = \frac{23}{3}$.
    • Equation: $y = -\frac{4}{3}x + \frac{23}{3}$.

Final Example

  • Example 6: $y = -\frac{2}{3}x + 4$, find perpendicular line through (6, -2).
    • Perpendicular slope: $\frac{3}{2}$.
    • Substitute $x = 6$, $y = -2$: $-2 = \frac{3}{2}(6) + b$.
    • Solve for $b$: $b = -11$.
    • Equation: $y = \frac{3}{2}x - 13$.

Conclusion

  • Practicing these steps with various examples helps solidify understanding of writing equations for parallel and perpendicular lines.