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Triangle Solutions with Cosines and Sines
Apr 18, 2025
Solving Triangles Using Law of Cosines and Law of Sines
Introduction
When given a triangle with different side and angle measures, specific laws in trigonometry can be used to find missing sides or angles.
Key laws:
Law of Cosines
and
Law of Sines
.
Example 1: Solving a Triangle with Given Sides and Angle
Given:
Side a = 10
Side b = 20
Angle C = 60 degrees
Type of Triangle:
Side-Angle-Side (SAS)
Using Law of Cosines
Formula:
[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) ]
Application:
Substitute: a = 10, b = 20, C = 60°
[ c^2 = 10^2 + 20^2 - 2(10)(20) \cdot \cos(60°) ]
[ c^2 = 100 + 400 - 400(0.5) ]
[ c^2 = 300 ]
[ c = \sqrt{300} = 10\sqrt{3} \approx 17.32 ]
Using Law of Sines
To Find Angle B
Formula:
[ \frac{c}{\sin(C)} = \frac{b}{\sin(B)} ]
Application:
[ \frac{17.32}{\sin(60)} = \frac{20}{\sin(B)} ]
Solve for sin(B): [ \sin(B) = 1 ]
Angle B = arcsin(1) = 90°
Finding Angle A
Angle A = 180° - 90° - 60° = 30°
Result:
The triangle is a right triangle.
Example 2: Solving a Triangle with All Three Sides
Given:
Side a = 7
Side b = 8
Side c = 9
Type of Triangle:
Side-Side-Side (SSS)
Using Law of Cosines
Finding Angle C
Formula:
[ \cos(C) = \frac{c^2 - a^2 - b^2}{-2ab} ]
Application
[ \cos(C) = \frac{81 - 49 - 64}{-2(7)(8)} ]
[ \cos(C) = \frac{-32}{-112} = \frac{2}{7} \approx 0.2857 ]
Angle C = arccos(0.2857) \approx 73.4°
Using Law of Sines
Finding Angle A
Formula:
[ \frac{c}{\sin(C)} = \frac{a}{\sin(A)} ]
Application:
[ \frac{9}{\sin(73.4)} = \frac{7}{\sin(A)} ]
Solve for sin(A): [ \sin(A) \approx 0.7453 ]
Angle A = arcsin(0.7453) \approx 48.2°
Finding Angle B
Angle B = 180° - 73.4° - 48.2° \approx 58.4°
Conclusion
Using Laws:
Use the Law of Cosines first to solve for angles when given all sides (SSS) or two sides and an included angle (SAS).
Then apply the Law of Sines for remaining angles or sides.
These methods provide a systematic approach to solving any triangle with given measurements.
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