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Vectors and Directional Angles
Jul 7, 2024
Lecture Notes: Vectors and Directional Angles
Magnitude of V
Magnitude Calculation:
Formula: |V| = (\sqrt{V_1^2 + V_2^2})
Given V in linear combination: V = V1(i) + V2(j)
Example:
V1 = 6, V2 = -6
Calculation: (\sqrt{6^2 + (-6)^2}) = (\sqrt{72})
Simplifying (\sqrt{72}):
Find the largest square number that divides 72.
72 = 36 * 2
Thus, (\sqrt{72} = 6\sqrt{2})
Breakdown:
Alternative methods: 72 = 12 * 6 and further break down as needed.
Directional Angle
**Calculating Directional Angle: **
Directional angle (\theta) using tangent:
(\tan(\theta) = \frac{V_2}{V_1} = \frac{-6}{6} = -1)
(\theta = \tan^{-1}(-1))
Result: (\theta = -45°)
Converting:
Negative angle (-45°) to positive direction by adding 360°: (315°)
Thus, (\theta = 315°)
Summary
Magnitude of vector V: (6\sqrt{2})
Directional angle (\theta): 315°
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