So when I solve Bhaskara's formula, my watch shook here, I messed up. I thought he was going to speak. Enough then will be two minus signs, or if you are learning the 2nd degree equation, you are confused on how to do the solution using the Bhaskara form, are you thinking that the Bhaskara formula is a Seven-Headed Beast, which is so difficult, I'm going to show you that it's not difficult, that it's very easy to solve, I'm going to explain it in detail so that you can rock your activities there, so when the statement of your activity asks you to solve from Bhaskara's formula one complete quadratic equation , here in this case I brought a complete one, okay, that in other cases we will solve when it is incomplete. And then the first part to solve in the Bhaskara way is to calculate the discriminant, but who is the discriminant? People take a look here, who is the discriminant when I calculate the delta, okay, so calculating the discriminant means finding the delta value, but who is the delta? The delta is what the coefficient B squared minus 4x is, notice this 4 is a fixed value it doesn't change, the a is the other coefficient and the c is the other coefficient. But where do I get these coefficients in the equation? The abc is not written here in my equation. How am I going to find it, so, before talking about the equation here, I'm going to give you a tip for those who want a very explanatory class from the beginning, okay, not that this isn't going to be us, people, because I always explain in detail , but with more examples I want to say, I'll let you go back to this complete class on quadratic equations, because here we're just going to solve this exercise so you can practice a little bit. So looking at this equation which is complete, we have the three coefficients there: oa, ob and c, remembering people, oa is that coefficient that is on the side of X squared, it is always on the side of X squared, b is that one coefficient that is on the side of X and c is that coefficient that is alone in the equation, which in this case would be minus one . The b would be the minus three, be careful, okay, because there are people who look here: whoever is on the side of the X is the three, so b is the three, just look at the sign, you have to be careful with the sign, okay , which will then change the entire result And the coefficient here is the one on the side of x squared is four So look how easy it is now, I already have the value of each coefficient because I managed to remove it here from mine equation, then we're going to take these values of each coefficient and we're going to put them here in the little discriminant formula. You saw how simple people are, so let's do this now. So starting there Delta is the same. So it starts with B squared, right? It's the B coefficient squared, the B coefficient is negative three, so it's going to be negative three. Detail you have to put a parenthesis is good, because otherwise it will be wrong - 3 squared then it will be minus four times, remember that I said that four is the fixed value every time it will have four, the ones that go change are the letters, o a four times oa, here is four times oc which is minus one, again I put it in parentheses. Next step now let's calculate: I have here now a numerical expression to solve , you know, I start with the power by doing minus 3 squared minus 3 squared will be equal to plus 9, so what do I do now? So now you can do 9 - and 4 then give the result and I multiply it here? People don't pay attention now that's why I said look here I have the numerical expression I solved the power and now what is the next operation to be solved in an expression? Is it subtraction or is it multiplication? The multiplication, so that's why pay close attention, there are students who do 9 - 4 is 5 and multiply here by four which is twenty and they already get everything wrong, and then they say it's difficult. You see it's not difficult, just be careful, I'm now going to do 4 x 4 which is 16 and 16 X 1 which is 16. Ok, but what about the sign game here the sign rule because there is multiplication between the factors then you need to apply the sign rule, so here this guy was minus, minus with minus will be in the plus multiplication, and then I found that the discriminant value of Delta is 25, so far so good, 25, it's not over, because the what does it mean to resolve a quadratic equation means to find the values for x that satisfy this equation what it means, so is to find the value of x, that here I didn't find the value of X, I found the value of Delta, but what now, now we let's go to the second part that we divided into two to make the calculations easier for you, maybe you learned everything in one, but I think it's more difficult to do, so we separate and then the other part look here look X there it made it easier, right because what I want is ox, x equals minus b plus or minus the square root of delta divided by two a, is there anything difficult there for you? The b you have is the coefficient B Or Delta you already have and the a you already have there we are going to find the x. So let's continue here now, look, so, it will be equal to x, then it will be minus b, so it's minus of the formula pay attention here too, okay, and it's minus of the coefficient well then it will be two minus signs so it will be minus or minus three and of course you then get the hang of it, do it straight there, people, more or less the square root of the Delta that gave Delta here inside the root that gave 25 and all of this will be divided by two times the a and the coefficient a is four, see again I just changed the value of each coefficient for what I had there then let's solve it now, so it's going to be x equals here guys look and if less here it's going to be more or it's going to be three more, I'm going to put three ok, more or less the square root of 25 is five ok and divided here by two times four which is eight now as I am solving an equation of the second degree or the highest exponent of X is two so that means that at most I will have two roots that is, two values for the equation, at most, okay? So let's go, I'm going to draw a little arrow here and I'm going to find out who will be the X1 people say x 1 x line there it will be then the three then I'm going to do the X1 using the more here, ok, but if you want to do it with less it will be the same later, I'll do it with more than standardize it for the students divided by 8 and I put the same in the wrong place and it was too high production I have to fix it I don't like it when it's wrong like this, X1 now how am I going to do it here o X2 or X2 lines, who wants to put X9 too, right people can play that little game, You can put X9 too, it will be what then, it will be three, now I will put the minus or 5 divided by 8, that's why I said you put less here if you put more here, the only sign that changed you saw that it was 1 was more or another was less between the terms. Ah, but why do you do that, more or less? Because when I'm calculating an equation that is the value of X, when I take the square root of 25 I can find two values that satisfy the square root of 25, because I'm looking for the value of x, which values would be plus five and minus five, that's why it's going to be plus or minus, ending up here now guys, I have three plus five which is going to be 8 and 8 / 8 so we have 1 integer, I managed to find the first root that answer that satisfies the equation, because if you take this number one that you got here and you put it here in your equation, it will be zero. Let's do it here or do it down here so it's going to be four times I'm going to do just that first root so you can visualize what it is to find the value of x, instead of x squared I'm going to put x that is worth 1, 1 to square is one. So it's going to be one, then it's going to be minus three times, three times X is one, so it's three times 1 minus 1 and that has to equal zero. Is this sentence going to be true equality that I put is going to be true four , times one here is four, mark there then doing it mentally, three times one gives 3. 4 - 3 gives one and taking one away from here gives zero. So, you saw that when I changed the value of X for what I found here, I got a true sentence. The value given here was equal to zero, which is marked there. So what does it mean to find the root, if it's called root is the value of X is find the Root, so also mark there it's not the root of the tree there, it's the root which is the result that the answer to the x that satisfies the equation okay , then ending the other one here, I'm going to do three - 5 is minus 2 - 2 by 8 so you can see that here I have a fraction that can be simplified. And then I can share here the numerator and denominator by two, so we're going to get minus now I'm going to put this number in the right place that it wasn't here, okay, two by two is 1, 8 by two is four so I found the other root that will be minus a quarter and then you will stay, there will be a little task, you will take this minus a quarter and you will do this check that I did. Do people need to do the verification every time I solve the quadratic equation? No, people here don't need it. I just did it to show you what it means to find the value of X. And then how do I give the answer, leave it like this, circle, make a drawing, then we put the answer in a solution set because I found it I solved the question I found the value for X . So it's going to be this one of set solution open key then I put it in ascending order okay, I'm going to start here with minus a quarter it won't be minus a quarter and the other root which was one. And then I separated it with a comma here, so the solution set was minus a quarter and one. Cnsegui solve the quadratic equation . And now you still think that the 2nd degree equation using bháskara's formula is a seven-headed bug or now it's easier for you to solve? Leave it in the comments for Giz, also take advantage of the fact that you are going to leave the comments there, subscribe to the Gis channel and leave that thumbs up for this tip, it wasn't a tip, no, it was a class, right people, on how to solve an equation high school and I'll see you in the next class bye!