Number of factors formula: (e1 + 1)(e2 + 1)(e3 + 1)..., where ei is the power of the i-th prime.
Example calculation yields 336 factors for 15!.
Highest Power of Prime Factors in Factorials
Calculating Highest Power
Example: Highest power of 2 in 15!.
Method: Successively divide by 2 and count how many times.
15 ÷ 2 = 7 (7 times)
7 ÷ 2 = 3 (3 times)
3 ÷ 2 = 1 (1 time)
Total: 11.
Finding Highest Power of a Prime
Example for a non-prime number (e.g., 6) in 60!:
Break down into prime factors: 6 = 2 × 3.
Calculate highest power of 2 and 3 separately.
Use the minimum of the two to find the highest power of 6.
Example Calculations
Highest power of 3 in 60!: 20 + 6 + 2 = 28.
Highest power of 5 in 60!: 60 ÷ 5 = 12 + 60 ÷ 25 = 2 = 14.
Leading to the conclusion that highest power of 10 in 60! depends on the number of 5s.
Trailing Zeros
Definition: The number of trailing zeros in a factorial is determined by the number of 10s in the factorization.
10 = 2 × 5.
In any factorial, 2s will outnumber 5s.
Therefore, trailing zeros = highest power of 5.
Calculation
Example: Find trailing zeros in 100!.
Step through divisions by 5:
100 ÷ 5 = 20 + 100 ÷ 25 = 4 = 24.
Result: 24 trailing zeros.
Summary
Factorials are foundational in combinatorics and number theory.
The process of finding prime factors and their powers in factorials is crucial for solving complex problems involving combinations, permutations, and trailing zeros.