the other kind of calorimetry problem that you will encounter is what we do with a bomb calorimeter so typically the words in the problem will say bomb calorimeter in it so just remember it's that sealed vessel that has all the other um materials in there and the big thing in there with a bomb calorimeter you should have a Capital C which is the heat capacity of the bomb calorimeter so that should be somewhere in the problem on here so what we're doing in here is we are taking this mass of glucose and we're burning it inside of a bomb calorimeter so we are com uh performing a combustion reaction so in a combustion reaction it should be exothermic so we should be releasing heat the temperature of the calorimeter increased from 23.8 De C to 35.6 De C and then the calorimeter contains 775 G of water and the bomb itself so here's the key it has a heat capacity and look at the units there 893 jewles per degrees celsus so we know we have a Capital C on here and now the question is how much heat was produced by the combustion of the glucose sample so we need to go ahead remember the sum of all the cubes are going to equal zero so then we have to ask ourselves what are the cues that are in the problem so the Q in there we have our Q the reaction and that's the combustion of the glucose so there's a combustion that's happening there plus we know that we have water in the calorimeter plus there's going to be a CU of the water because there's going to be some heat transfer of the water itself and then it tells us the bomb has some sort of heat capacity so then there's a of the calorimeter we're going to add all those up to be zero so if we go back to what is the system and what are the surroundings this PE the reaction is what we're interested so that's our system everything else is our surroundings but I like to break it up into the separate cues so we don't know what our Q of the reaction is we can calculate the Q of our water as the M lowercase uh C delta T so that's our Mass specific heat capacity and our change in temperature and then we are also told what the heat capacity of our calorimeter is times delta T so our change in temperature and how that will all equal zero so this is what we want to calculate we know that we have our mass of our water is 700 75 G our c is 4.184 Jew per degrees Celsius G or you'll see GRS per degree celsius and our change in temperature is going to be 35.6 minus 23.8 Dees C our Capital C on here is given to us as 893 jewles per de Cs and then we're going to multiply that by our same temperature final initial so our delta T is 35.6 minus 23.8 degrees cus on here so we can go ahead and calculate this out our Q the reaction if we end up calculating all of this out we should get we should get a value of uh 38,000 300 jewles we calculate this out over here um and we should have 10,500 Jews we set that equal to zero so we go ahead and add this up our Q of the reaction plus 48,800 Jew equal 0 and then our Q of the reaction should equal - 48,800 Jew and that should make sense to us because we have a negative number we should have some sort of exotherm reaction so we have a negative value it makes sense in terms of the combustion of our glucose and a lot of times what we will do is we will actually uh report these values in kilog so make sure you look at your answer to see what units you're going to use because you may have to convert this as - 4880 jewles you might have to convert in k there's one k for every 1,000 jewles I never skip writing these dimensional analyses so you will get a final number of minus 48.8 K so you'll have to look at your problem to see which value uh you might be calculating whether it is kles or jewels