Understanding Electric Field of Charged Ring

Sep 13, 2024

Lecture 6: Electric Charges and Field

Introduction

  • Topic: Finding electric field on the axis of a charged ring
  • Importance: Commonly asked in board exams and competitions.
  • Lecturer: Alok Pandey

Overview of a Charged Ring

  • Charged Ring: Continuous charge distribution.
  • Electric field calculation is based on charge distribution rather than point charges.
  • For a point charge, electric field is calculated as:

    [ E = \frac{kQ}{x^2} ]

Electric Field on the Axis of a Charged Ring

  • Consider a ring with total charge Q uniformly distributed.
  • We need to find the electric field at a point along the axis at a distance x from the center of the ring.

Electric Field Calculation Steps

  1. Charge Element:
    • Consider a small element of charge dq.
    • Calculate electric field dE due to dq.
    • Use the formula for point charge:

      [ dE = \frac{k dq}{r^2} ]
    • Components of dE:
      • dE cos(θ) contributes to the electric field along the axis.
      • dE sin(θ) cancels out due to symmetry.
  2. Integration:
    • Total electric field is the sum of all dE cos(θ) components.
    • Use integration over the entire ring:

      [ E = \int dE cos(θ) = \frac{kQx}{(R^2 + x^2)^{3/2}} ]
  3. Final Expression for Electric Field:
    • At a distance x from the center of the ring:

      [ E = \frac{kQx}{(R^2 + x^2)^{3/2}} ]
      • Where R is the radius of the ring.

Special Cases

  • At the Center of the Ring:
    • When x = 0, E = 0 (due to symmetry).
  • At Infinity:
    • As x approaches infinity, E approaches 0.

Graph of Electric Field (E) vs Distance (x)

  • The graph shows E is 0 at both the center and at infinity, with a maximum value in between.
  • Electric field is positive on one side of the ring and negative on the other due to the nature of vector quantities.

Finding Maximum Electric Field

  • To find the value of x that maximizes E:
    • Derive the expression for E with respect to x and set it to zero.
  • Resulting value of x for maximum E:
    • x = ±R / √2
  • Maximum Electric Field Value:

    [ E_{max} = \frac{2kQ}{3\sqrt{3}R^2} ]_

Conclusion

  • Understanding the electric field on the axis of a charged ring is essential for both board exams and competitive examinations.
  • Reminder to keep studying and practicing.