Sep 25, 2024
Differential Equations (7-8 lectures)
Integrals (3 lectures)
Calculus of Functions in Two Variables
dy/dx = f(x), solvable by direct integration.∫u dv = uv - ∫v du∫ x² sin(x) dxu = x², dv = sin(x) dxx² (-cos(x)) + 2 ∫ x cos(x) dx∫ (2x - 1) ln(x) dxu = ln(x), dv = (2x - 1) dxdy/dx = a(x) b(y)x(y² - 1) + y(x² - 1) dy/dx = 0∫(y/(y² - 1) dy) = -∫(x/(x² - 1) dx).