Sep 25, 2024
Differential Equations (7-8 lectures)
Integrals (3 lectures)
Calculus of Functions in Two Variables
dy/dx = f(x)
, solvable by direct integration.∫u dv = uv - ∫v du
∫ x² sin(x) dx
u = x²
, dv = sin(x) dx
x² (-cos(x)) + 2 ∫ x cos(x) dx
∫ (2x - 1) ln(x) dx
u = ln(x)
, dv = (2x - 1) dx
dy/dx = a(x) b(y)
x(y² - 1) + y(x² - 1) dy/dx = 0
∫(y/(y² - 1) dy) = -∫(x/(x² - 1) dx)
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