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Understanding Least Squares Solutions
Sep 15, 2024
Notes on Least Squares Solution
Introduction to Matrix Equation
Consider the equation: ( Ax = b )
( A ) is an ( n \times k ) matrix
( x ) is in ( R^k ) (k-dimensional vector)
( b ) is in ( R^n ) (n-dimensional vector)
No Solution Situation
If ( Ax = b ) has no solution:
No set of weights on columns of ( A ) can equal ( b )
This implies: ( b ) is not in the column space of ( A )
Linear combinations of column vectors of ( A ) cannot equal ( b )
Column Space Visualization
Visualizing the column space of ( A ):
Assume it forms a plane in ( R^n )
If ( b ) does not lie in this plane, it indicates no solution.
Finding a "Closest" Solution
Although there is no exact solution, we can find an approximate solution:
Goal: Find ( x^* ) such that ( Ax^* ) is as close to ( b ) as possible.
Define "closeness" in terms of minimizing the length of the vector ( b - Ax^* ).
Minimization of Length
To minimize:
( ||b - Ax^*||^2 = (b_1 - v_1)^2 + (b_2 - v_2)^2 + ... + (b_n - v_n)^2 )
Least Squares Solution Definition
The resulting solution is termed the
least squares solution
When ( b ) is not in the column space of ( A ), we seek an ( x^* ) such that:
( Ax^* ) equals the projection of ( b ) onto the column space of ( A )
Projection and Orthogonality
The difference vector ( Ax^* - b ) is orthogonal to the column space of ( A ).
It belongs to the
orthogonal complement
of the column space, which is the null space of ( A^T ).
Deriving the Least Squares Solution
From previous findings:
( A(x^*) - b ) is in the null space of ( A^T )
Thus, when multiplied by ( A^T ):
( A^T(Ax^* - b) = 0 )
Rearranging gives:
( A^T A x^* = A^T b )
Conclusion
The equation ( A^T A x^* = A^T b ) helps find the least squares solution even if the direct solution to ( Ax = b ) doesn't exist.
This method minimizes the error, resulting in the best approximation to the solution.
The concept is foundational in many applications, particularly in data fitting and regression analysis.
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