Jul 20, 2024
Position, Velocity, Acceleration: Use derivatives and integrals.
position = 2T^3 - 6T + C₀ ⟹ velocity = 6T^2 - 6
velocity = 6T^2 - 6 ⟹ acceleration = 12T
Constant Velocity and Acceleration:
distance = velocity × time (x = v*t)
aₛ = 9.8 m/s²
, typically approximated as -10 m/s²
.F = ma
(Force equals mass times acceleration).-BV
or -BV²
.m
slowing down due to air resistance, resulting in a differential equation.Fₓ = (m*v²)/R
Fg = (G * m₁ * m₂) / r²
W = F ⋅ d ⋅ cos(θ)
(force over distance in the force's direction).KE = (1/2)mv²
Uᵍ = mgh
Uₑ = (1/2)kx²
W = ΔK
p = mv
J = Δp = ∫F dt
J = Δp
θ
, angular velocity ω = dθ/dt
, angular acceleration α = dω/dt
I = Σmᵢrᵢ²
I = ∫r²dm
τ = rFsin(θ)
τ = Iα
L = Iω
for rotating objectsL = r × p
for point massesF = -kx
x(t) = A cos(ωt + φ)
ω = √(k/m)
T = 2π√(m/k)
T = 2π√(L/g)
with small angle approximation.v = u + at
, s = ut + (1/2)at²
, v² = u² + 2as
F = ma
, τ = Iα
KE = (1/2)mv²
, U = mgh
p = mv
, J = ∫F dt
L = Iω
, τ = rFsin(θ)