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Chi-Squared Test Lecture
Jul 7, 2024
Chi-Squared Test Lecture
Introduction
Focus: Testing two or more proportions using chi-squared test
Proportion: Calculation based on categorical variables
Example: Testing college students' food preferences (pizza vs. salad bar) among freshmen and seniors
Setup and Definitions
Categorical Variables
: Different categories (e.g., dog, cat, horse)
Chi-Squared Statistic
: Calculated to test the claim that proportions are the same
Expected Counts
:
Calculate for each cell
Formula: (Row Total * Column Total) / Table Total
Assumes null hypothesis (H0) is true
Table Layout
2x2 Table
: 2 rows and 2 columns
2x3 Table
: 2 rows and 3 columns
4x2 Table
: 4 rows and 2 columns
Example 1: Cats and Dogs Leisure Activity
Cats: 16 total
Dogs: 17 total
Activities: Playtime and Nap
Null Hypothesis (H0): No relationship between type of animal and activity preference
Expected Counts Calculation:
Playtime (Dogs)
: (17 * 15) / 33 = 7.6
Nap (Dogs)
: (17 * 18) / 33 = 9.2
Similar calculations for cats
Observed Data vs. Expected Count
: Compare to determine if null hypothesis can be rejected
Hypothesis Testing
Null Hypothesis (H0)
: No relationship (independent variables)
Alternate Hypothesis (H1)
: Relationship exists (dependent variables)
Chi-Squared Test Statistic
: Formula
Sum of (Observed Count - Expected Count)^2 / Expected Count for each cell
Use chi-squared distribution table or software for p-value
Example 2: Coke vs Pepsi Preference
Test: Can people identify preference between Coke and Pepsi?
Methods: Blind taste test after recording initial preference
Observed Data: How many people correctly identified their preference
Expected Count Calculation
:
Example: (312 * 270) / 512 = 164 (Own Coke)
Requirements for Chi-Squared Test:
Simple Random Sample with independent populations
All expected counts ≥ 1
At least 80% of expected counts are ≥ 5
Calculation and Interpretation:
Chi-Squared Statistic: 5.17 (example)
Degrees of Freedom: (2-1) * (2-1) = 1
P-value: Calculated via software (e.g., Excel)
Reject Null Hypothesis if p-value < alpha (typically 0.05)
Conclusion
Chi-squared test helps determine relationships between categorical variables
Following the steps and conditions ensures accurate hypothesis testing
Example showed real-world use in determining beverage preferenceё
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