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Probability and Odds
Jun 14, 2024
Lecture Notes: Probability and Odds
Introduction
Topic
: Exploring probability and defining odds
Focus
: Calculating odds in favor and odds against using probability
Definitions and Concepts
Event and Complement
Event
: The occurrence we are interested in (e.g., winning the gray cup)
Probability of Event (A)
:
Given as 25% or 0.25 (can also be written as 1/4)
Complement of Event (A')
:
The event not occurring
Notated as A' or A-bar
Probability of Complement (A'): 1 - P(A) = 3/4
Odds
Odds in Favor
:
Calculated as: P(A) / P(A')
Example: If P(A) = 1/4 and P(A') = 3/4
Odds in favor = (1/4) / (3/4) = 1/3
Simplified to: 1 to 3
Odds Against
:
Calculated as: P(A') / P(A)
Example: Using the same P(A) and P(A') as above
Odds against = (3/4) / (1/4) = 3/1
Simplified to: 3 to 1
Example Problems
Example 1: Choosing a Face Card
Scenario
: Mario chooses a single card from a standard deck where all hearts are in Janara's hand
Face Cards
: Jack, Queen, King of hearts
Total Hearts
: 13
Face Cards
: 3
Non-Face Cards
: 10
Odds in Favor
:
Probability of face card = 3/13
Probability of non-face card = 10/13
Odds in favor = 3 to 10
Example 2: Day of the Week
Scenario
: What are the odds against a randomly chosen day being Sunday?
Probability of Sunday
: 1/7
Probability of Not Sunday
: 6/7
Odds Against
:
Odds against = 6/1
Which is: 6 to 1
Example 3: College Gift Card
Scenario
: Determining the probability from given odds
Odds Against
: 57 to 43 that a student is not in the first year
Calculating Probability
:
Adds up odds to get total outcomes: 57 + 43 = 100
Probability of being in the first year = 43/100 = 43%
Example 4: Hockey Shootout
Scenario
: Deciding who should take the shot based on past success rates
Ellen
: 8 goals out of 13 attempts (Probability: 0.615)
Brittany
: 10 goals out of 17 attempts (Probability: 0.588)
Josie
: 2 goals out of 3 attempts (Probability: 0.667)
Decision
: Based on highest probability or consistency (Ellen)
Example 5: Charity Carnival Games
Scenario
: Comparing odds against winning two games
Bim
: Odds against = 5 to 2 (converts to odds in favor = 2 to 5)
Zap
: Odds against = 7 to 3 (converts to odds in favor = 3 to 7)
Probabilities
:
Winning Bim: 2/7 = 0.286
Winning Zap: 3/10 = 0.3
Decision
: Higher probability of winning Zap
Summary
Odds in Favor
: P(A) / P(A')
Odds Against
: P(A') / P(A)
Clarification
: Odds are not the same as probability ratios; total outcomes cancel out in odds
Next Steps
Upcoming Topics
: Counting methods, set theory, and notation for solving more complicated probabilities
Thanks for watching!
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