Understanding Concentration of Solutions

Aug 18, 2024

Lecture: Concentration of Solutions

Introduction

  • Presenter: Andre
  • Topic: Main ways of expressing concentration of solutions
  • Structure: Different units of concentration and examples

Molarity (M)

  • Definition: Moles of solute over liters of solution
  • Components:
    • Solute: Substance being dissolved (e.g., salt in a saltwater solution)
    • Solvent: Substance doing the dissolving (e.g., water in a saltwater solution)
  • Example Problem:
    • Given a solution that evaporates from 0.15L to 0.105L, find the new concentration
    • Use formula: ( M_1 V_1 = M_2 V_2 )
    • Calculation: ( M_2 = \frac{M_1 \times V_1}{V_2} = 0.794 \text{ M} )
  • Key Point: Concentration increases as solvent evaporates

Molality (m)

  • Definition: Moles of solute over kilograms of solvent
  • Example Problem:
    • Given 571.4g of ( H_2SO_4 ) and density 1.329g/cm³
    • Convert volume units: 1 cm³ = 1 mL, 1000 cm³ = 1L
    • Calculate mass of solution and solvent:
      • Solution mass: 1329g (from density)
      • Solvent mass: 1329g - 571.4g = 757.6g = 0.7576 kg
    • Calculate moles of solute using molar mass: ( 5.83 \text{ moles} )
    • Molality: ( 7.69 \text{ m} )

Mole Fraction

  • Definition: Moles of solute over total moles of solution
  • Example Problem:
    • Mixing 25g of water and 25g of ethanol
    • Calculate moles for each: ( 1.388 \text{ moles of } H_2O ), ( 0.543 \text{ moles of ethanol} )
    • Total moles: 1.931
    • Mole fraction:
      • Water: ( \frac{1.388}{1.931} = 0.719 )
      • Ethanol: ( \frac{0.543}{1.931} = 0.281 )

Percent by Mass

  • Definition: Mass of solute over mass of solution (in grams) multiplied by 100%
  • Example Problem:
    • Solution with 36.5g NaCl and total mass 3.55g
    • Calculation: ( \frac{36.5}{3.55} \times 100% = 10.3% )

Percent by Volume

  • Definition: Volume of solute over volume of solution multiplied by 100%
  • Example Problem:
    • 25 mL of ethanol mixed to make 200 mL total solution
    • Calculation: ( \frac{25}{200} \times 100% = 12.5% )

Conclusion

  • Overview of various concentration expressions: molarity, molality, mole fraction, percent by mass, and percent by volume
  • Encouragement to watch the next lecture on equilibrium and aqueous solutions