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Understanding Molar Mass and Conversions

Apr 29, 2025

Lecture Notes: Calculating Molar Mass and Converting Grams to Moles

Introduction

  • Presenter: Melissa Maribel
  • Focus: Understanding molar mass, converting grams to moles and vice versa
  • Audience: Students serious about Chemistry

Types of Mass in Chemistry

  • Atomic Mass
    • Measured in atomic mass units (amu)
  • Molar Mass
    • Measured in grams per mole (g/mol)
    • Represents the mass of a mole of an element

Calculating Molar Mass

  • Individual Element Example: Carbon
    • Use periodic table: Carbon = 12.011
    • Molar mass: 12.011 g/mol
  • Compound Example: Carbon Dioxide (CO2)
    • Carbon: 12.011 g/mol + Oxygen: 2 × 16 g/mol = 32 g/mol
    • Total molar mass: 44.011 g/mol

Conversion Factors

  • Conversion factors involve two different units (e.g., grams and moles)
  • Molar Mass serves as a conversion factor
    • Useful for converting between grams and moles

Example 1: Converting Grams to Moles

  • Problem: How many moles in 5.3 grams of iron chloride?
  • Given: 5.3 grams iron chloride
  • Find: Moles of iron chloride
  • Plan: Convert using molar mass
    • Molar Mass of Iron Chloride: Iron = 55.85, Chlorine = 35.45 × 2
    • Total: 126.75 g/mol
  • Calculation:
    • Setup conversion with units aligned to cancel
    • Result: 0.042 moles of iron chloride

Example 2: Converting Moles to Grams

  • Problem: Find the mass of 0.30 moles of magnesium nitrate
  • Given: 0.30 moles magnesium nitrate
  • Find: Grams of magnesium nitrate
  • Plan: Convert using molar mass
    • Molar Mass of Magnesium Nitrate: Magnesium = 24.31, Nitrogen = 14.01 × 2, Oxygen = 16 × 6
    • Total: 148.33 g/mol
  • Calculation:
    • Setup conversion to align units for cancellation
    • Result: 44 grams of magnesium nitrate (considering two significant figures)

Conclusion

  • Encouragement to practice conversions
  • Offer for free live tutoring and additional resources
  • Call to action to subscribe and engage with further content

  • Note: Practice problems and tutoring resources are available for further study.