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Understanding Polynomial and Rational Inequalities (vid 31)
Feb 12, 2025
Lecture Notes: Polynomial and Rational Inequalities
1. Polynomial Inequalities
Example Problem
: Solve (x^3 - 4x < 0)
Factorization
: (x(x^2 - 4) = x(x-2)(x+2))
Critical Points
: x = 0, 2, -2
Sub-intervals
:
((-\infty, -2))
((-2, 0))
((0, 2))
((2, \infty))
Test Points
:
(x = -3): negative
(x = -1): positive
(x = 1): negative
(x = 3): positive
Solution
: ((-\infty, -2) \cup (0, 2))
2. Rational Inequalities
Example Problem
: (\frac{2x+4}{x-1} < 1)
Rearrange
: (\frac{2x+4}{x-1} - 1 < 0)
Common Denominator
: (\frac{2x+4 - (x-1)}{x-1} < 0)
Simplify
: (\frac{x+5}{x-1} < 0)
Critical Points
:
Numerator zero at (x = -5)
Denominator zero at (x = 1)
Sub-intervals
:
(x < -5)
((-5, 1))
((1, \infty))
Solution
:
Test Points
:
(x = -6): positive
(x = 0): negative
(x = 2): positive
For (< 0), solution is ((-5, 1))
For (\leq 0), solution is (
-5, 1)) since (x \neq 1).
3. Greater than or Equal Rational Inequalities
Example Problem
: (\frac{2x-1}{x^2-9} \geq 0)
Factorization
:
Denominator: ((x-3)(x+3))
Critical Points
:
Numerator zero at (x = \frac{1}{2})
Denominator zero at (x = \pm 3)
Sub-intervals
:
(( -\infty, -3))
((-3, \frac{1}{2}))
((\frac{1}{2}, 3))
((3, \infty))
Test Points
:
(x = -4): negative
(x = 0): positive
(x = 1): negative
(x = 4): positive
Solution
:
Positive intervals: ((-3, \frac{1}{2}] \cup (3, \infty))
Cannot include (x = \pm 3) due to zero in the denominator.
Summary
Key Takeaway
: Solving polynomial and rational inequalities involves:
Factoring the polynomial/rational expression
Identifying critical points by setting numerator and denominator to zero
Dividing the number line into intervals
Testing intervals for sign determination
Being cautious with inequalities involving denominators to avoid division by zero.
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