πŸ“Š

Displacement-Time Graphs and Motion Analysis

Sep 7, 2025

Overview

The lesson covers how to interpret displacement-time graphs, analyze motion using these graphs, and calculate distance, speed, and velocity for various movement scenarios.

Understanding Displacement-Time Graphs

  • Displacement-time graphs show an object's position relative to a starting point over time.
  • Positive displacement values indicate movement in the chosen positive direction (e.g., right, east, or north).
  • Negative displacement shows movement in the opposite (negative) direction.
  • Flat (horizontal) segments on a displacement-time graph mean the object is not moving.

Key Examples and Calculations

Example 1: Walking from Home

  • The person walks 4 meters right, returns to the house, then goes 4 meters left (negative).
  • Total distance walked: 4 m (right) + 8 m (to -4 left) = 12 meters.
  • Average speed: 12 m / 15 s = 0.8 m/s.
  • At 10 and 15 seconds, the person is 4 meters left of the house.
  • Between 10-15 seconds, the person is stationary.
  • Velocity (5-10 s): (-4 - 4) / (10 - 5) = -1.6 m/s (left).

Example 2: Cycling East and West

  • Moves 60 meters east, stops, returns home, then 40 meters west, then back home.
  • Total distance: 60 + 60 + 40 + 40 = 200 meters.
  • Average speed: 200 m / 55 s = 3.64 m/s.
  • At 30 s: back at starting position (0 meters).
  • At 35 s: 20 meters west of the house.
  • Velocity (15-40 s): (-40 - 60) / (40 - 15) = -4 m/s (west).

Example 3: Sarah Walking North and South

  • Goes 2 m north, pauses, returns to start, goes 1 m south, pauses, returns to start.
  • Total distance: 2 + 2 + 1 + 1 = 6 meters.
  • At 7 s: 1 meter south of starting point.
  • Velocity (0-2 s): (2 - 0) / (2 - 0) = 1 m/s north.
  • Velocity (4-6 s): (-1 - 2) / (6 - 4) = -1.5 m/s south.
  • Velocity (6-8 s): (-1 - -1) / (8 - 6) = 0 m/s.

Example 4: Greg Sprinting West/East

  • Sprints 8 m west, stops, returns to start, 8 m east, stops, returns to start.
  • Velocity (0-2 s): (8 - 0) / (2 - 0) = 4 m/s west.
  • Velocity (4-8 s): (-8 - 8) / (8 - 4) = -4 m/s (4 m/s east).
  • Velocity (8-10 s): (-8 - -8) / (10 - 8) = 0 m/s.

Example 5: Boat Moving East and West

  • Moves 40 m east, pauses, goes to -40 m west, then to 20 m east, pauses, returns to start.
  • Velocity (30-50 s): (-40 - 40) / (50 - 30) = -4 m/s (west).
  • Velocity (0-30 s): (40 - 0) / (30 - 0) = 1.33 m/s east.
  • From G to H, boat is stationary (not moving).
  • Total distance: 40 + 80 + 60 + 20 = 200 meters.

Key Terms & Definitions

  • Displacement β€” Change in position from the starting point, including direction (vector).
  • Distance β€” Total length of the path traveled, regardless of direction (scalar).
  • Speed β€” Distance traveled divided by time taken (scalar), (\text{speed} = \frac{\text{distance}}{\text{time}}).
  • Velocity β€” Displacement divided by time taken (vector), (\text{velocity} = \frac{\Delta \text{displacement}}{\Delta \text{time}}).
  • Stationary β€” No change in displacement over time; object is not moving.

Action Items / Next Steps

  • Practice drawing and interpreting displacement-time graphs for various movements.
  • Solve additional problems calculating distance, speed, and velocity from different graphs.
  • Review the definitions and differences between distance/displacement and speed/velocity.
  • Complete any assigned homework or reading on motion and graphs as instructed.