Solving Radical Equations
Key Steps in Solving a Radical Equation
- Isolate the Radical: Make sure the radical is alone on one side of the equation.
- Raise Both Sides to the Power of the Index: This will remove the radical.
- Solve the Resulting Equation: After eliminating the radical, solve the equation as usual.
- Check Solutions: Substitute solutions back into the original equation to verify their validity.
Example 1
Equation: ( \sqrt{x + 6} = x + 4 )
- Isolate the Radical: Radical is already isolated on the left.
- Square Both Sides (index is 2):
- Left side: ( (\sqrt{x + 6})^2 = x + 6 )
- Right side: ( (x + 4)^2 = x^2 + 8x + 16 )
- Solve Resulting Equation:
- Equation becomes: ( x + 6 = x^2 + 8x + 16 )
- Rearrange to form a quadratic: ( 0 = x^2 + 7x + 10 )
- Factor: ( (x+5)(x+2) = 0 )
- Solutions: ( x = -5 ) or ( x = -2 )
- Check solutions:
- For ( x = -5 ): ( \sqrt{-5+6} \neq -5+4 ) (Extraneous)
- For ( x = -2 ): ( \sqrt{-2+6} = -2+4 ) (Valid)
Conclusion: Valid solution is ( x = -2 ).
Example 2
Equation: ( \sqrt{4x + 9} - 1 = x )
- Isolate the Radical:
- Add 1 to both sides: ( \sqrt{4x + 9} = x + 1 )
- Square Both Sides:
- Left side: ( 4x + 9 )
- Right side: ( (x + 1)^2 = x^2 + 2x + 1 )
- Solve Resulting Equation:
- Equation becomes: ( 4x + 9 = x^2 + 2x + 1 )
- Rearrange: ( 0 = x^2 - 2x - 8 )
- Factor: ( (x-4)(x+2) = 0 )
- Solutions: ( x = 4 ) or ( x = -2 )
- Check solutions:
- For ( x = 4 ): ( \sqrt{4\times4 + 9} - 1 = 4 ) (Valid)
- For ( x = -2 ): ( \sqrt{4\times-2 + 9} - 1 \neq -2 ) (Extraneous)
Conclusion: Valid solution is ( x = 4 ).
Important Notes
- Extraneous Solutions: Solutions that do not satisfy the original equation once checked.
- Always check solutions in the context of the original equation to confirm validity.
This method is crucial for solving equations involving radicals and avoiding errors due to extraneous solutions.