🏗️

Understanding Method of Sections for Trusses

Apr 18, 2025

Lecture Notes: Method of Sections for Trusses

Introduction

  • Method of Joints vs. Method of Sections
    • Method of Joints: Useful for solving large numbers of truss members.
    • Method of Sections: Efficient for finding forces in a few specific members without solving the entire truss.

Key Concepts

  • Equilibrium of Sections:
    • Any segment of a truss in equilibrium means the whole truss is also in equilibrium.
    • Use equilibrium equations or moment equations to solve for unknowns.

Steps to Solve Using Method of Sections

  1. Find Reactions at a Support:
    • Determine reactions at one support to simplify calculations.
  2. Section the Truss:
    • Cut through the members you want to solve.
    • Treat the cut members as external forces acting on the section.
  3. Assume Directions:
    • Assume directions for forces; negative results indicate opposite directions.
  4. Use Equilibrium Equations:
    • Apply equations of equilibrium or moment equations to solve for forces.

Important Notes

  • Internal vs External Forces:
    • Treat cut members as external forces while solving.
  • Compression vs Tension:
    • Force towards a pin: Compression
    • Force leaving a pin: Tension

Example Problems

Problem 1: Solving Members GH, BC, BG

  • Objective: Find forces in members GH, BC, BG.
  • Steps:
    1. Determine reactions at pin A.
    2. Cut through desired members and forget the opposite side.
    3. Assume forces directions and apply moment equations:
      • Moment about point B to eliminate forces BC, BG.
      • Moment about pin A to solve for force BG.
      • Moment about point H to solve for force GH.
  • Conclusion: All forces assumed correctly; GH in compression, BC in tension, BG in tension.

Problem 2: Solving Members BF, BG, AB

  • Objective: Find forces in members BF, BG, AB.
  • Steps:
    1. Cut truss to isolate top section.
    2. Moment about point B to solve for FG.
    3. Moment about point D to solve for force BG.
    4. Equation for y-axis forces to solve for force AB.
    5. Isolate joint F to identify BF as a zero-force member.
  • Conclusion: Efficiently used method of sections with minimal equations.

Problem 3: Solving Members DC, HC, HI

  • Objective: Determine forces in members DC, HC, HI.
  • Steps:
    1. Calculate reactions at the roller with a moment equation about point A.
    2. Cut through members and assume directions.
    3. Moment about point H to solve for DC.
    4. Equation for y-axis forces to solve for force HI.
    5. Equation for x-axis forces to solve for force HC.
  • Conclusion: DC in compression, HI and HC in tension.

Problem 4: Solving Members JI, DE

  • Objective: Find forces in members JI and DE.
  • Steps:
    1. Determine reaction at roller G with a moment equation about point A.
    2. Cut truss to isolate members.
    3. Moment about pin I to solve for DE.
    4. Moment about point E to solve for JI.
  • Conclusion: DE in tension, JI in compression.

Conclusion

  • Advantages of the Method:
    • Quickly solves for specific members without extensive calculations.
    • Utilizes simple equilibrium concepts.
  • Encouragement to share and review materials to reinforce understanding.