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Understanding Equilibrium Constants Kc and Kp
Jan 6, 2025
Lecture on Equilibrium Constants (Keq, Kc, Kp)
Introduction
Equilibrium constants can be expressed in terms of concentrations (Kc) or pressures (Kp).
Kc is used when dealing with concentrations.
Kp is used when dealing with gases and can utilize partial pressures.
Example of Equilibrium Expression
Consider the reaction: 2 SO3(g) ⇌ 2 SO2(g) + O2(g)
Kc expression:
[ Kc = \frac{[SO2]^2[O2]}{[SO3]^2} ]
Kp expression:
[ Kp = \frac{(P_{SO2})^2(P_{O2})}{(P_{SO3})^2} ]
Note: Use parentheses to indicate what's being squared or cubed.
Relationship Between Kc and Kp
Kp and Kc are not numerically equal due to different units.
Conversion between Kc and Kp:
[ Kp = Kc \times (RT)^{\Delta n} ]
( \Delta n ) is the change in moles of gas (products minus reactants).
Example: For 2 SO3(g) ⇌ 2 SO2(g) + O2(g):
Products: 2 moles SO2 + 1 mole O2 = 3 moles
Reactants: 2 moles SO3 = 2 moles
( \Delta n = 3 - 2 = 1 )
Unitless Nature of Equilibrium Constants
Equilibrium constants (Kc, Kp) have no units.
Values are referenced against a standard (1 M for concentrations, 1 atm for pressures) which cancels units.
Example: NO2 concentration of 1.5 M is considered as 1.5/1 M, leading to a unitless expression.
Treatment of Solids and Liquids in Equilibrium
Concentrations of pure solids and liquids are constant and don’t appear in equilibrium expressions.
Their activity is considered as 1.
Example of Equilibrium with Solids and Gases
CaCO3(s) ⇌ CaO(s) + O2(g)
Equilibrium expression: ( K = P_{O2} )
Only O2(g) is included because CaCO3 and CaO are solids.
Fe2O3(s) + 3CO(g) ⇌ 2Fe(s) + 3CO2(g)
Products/Reactants: Include gases only
Equilibrium expression:
[ K = \frac{[CO2]^3}{[CO]^3} ]
Solid components are excluded from the equation.
Conclusion
Understanding when to use Kc vs. Kp is key in equilibrium chemistry.
Consideration of phases (solid, liquid, gas) affects the formulation of equilibrium expressions.
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