Coconote
AI notes
AI voice & video notes
Try for free
📐
Quadratics Lecture Overview
Sep 13, 2024
📄
View transcript
🤓
Take quiz
Notes on Quadratics Lecture
Introduction
Discussed past purpose related to quadratics.
Question 1: Finding Constant C
Problem
: Find value of C for line ( y = 2x + C ) tangent to curve ( y^2 = 4x ).
Process
:
Convert curve into ( y = 2 \sqrt{x} ).
Set ( 2x + C = 2 \sqrt{4x} ).
Square both sides to eliminate square root:
( (2x + C)^2 = 4x ) leads to ( 4x^2 + 4Cx + C^2 - 4x = 0 ).
Identify coefficients: ( a = 4, b = 4C - 4, c = C^2 ).
Set discriminant ( b^2 - 4ac = 0 ) for tangency:
Solve ( (4C - 4)^2 - 4(4)(C^2) = 0 ).
Arrive at ( C = 0.5 ) or ( C = \frac{1}{2} ).
Question 2: Finding Real Roots
Problem
: Solve ( \frac{18}{x^4} + \frac{1}{x^2} = 4 ).
Process
:
Multiply through by ( x^4 ) to clear the denominator:
Resulting in ( 18 + x^2 = 4x^4 ).
Rearranging gives ( 4x^4 - x^2 - 18 = 0 ).
Substitute ( a = x^2 ): leads to ( 4a^2 - a - 18 = 0 ).
Use quadratic formula to find ( a ): roots are ( a = \frac{9}{4}, a = -2 ).
Determine real roots: ( x = \pm \frac{3}{2} ).
Question 3: Determine Set of Values for K
Problem
: Find K such that line ( y = 4x + K ) does not intersect curve ( y = x^2 ).
Process
:
Set up the equation: ( x^2 - 4x - K = 0 ) and set discriminant ( b^2 - 4ac < 0 ).
Calculate: ( 16 + 4K < 0 ) leading to ( K < -4 ).
Question 4: K for Two Distinct Points
Problem
: Same format, line ( y = ax - 4 ) and curve ( y = 2x^2 - 2x ).
Process
:
Set up ( 2x^2 - (2 + K)x + 4 = 0 ).
Apply discriminant condition for distinct points.
Final set of values is ( K < -6 ) or ( K > 2 ).
Question 5: K with No Intersection
Problem
: Line ( 2y = x + K ) not intersect curve ( y = 2x^2 - 4x + 7 ).
Process
:
Rewrite line as ( y = \frac{x + K}{2} ).
Discriminant analysis yields ( K < \frac{31}{8} ).
Question 6: K for No Common Points
Problem
: Calculate K for curve ( y = Kx^2 + 1 ) and line ( y = Kx ).
Process
:
Set ( Kx^2 - Kx + 1 = 0 ) and solve discriminant ( K(K - 4) < 0 ).
Range for K is ( 0 < K < 4 ).
Question 7: Finding P and Q
Problem
: Given roots -3 and 5 of equation ( x^2 + px + q = 0 ).
Process
:
Set up equations: ( 3p - 9 = -5p - 25 ) leading to ( p = -2 ), ( q = -5 ).
Question 8: Finding M for Intersection
Problem
: Line ( y = mx + 4 ) intersects curve at two distinct points.
Process
:
Set up discriminant condition and solve quadratic to find range for M: ( M < -10 ) or ( M > 2 ).
Question 9: K for Tangency
Problem
: Line ( y = x/k + k ) tangent to curve ( y = 4 ).
Process
:
Set ( kx^2 - 4x + 4k = 0 ) and solve for K yielding ( K = -1 ).
Question 10: Final Tangent Problem
Problem
: Line ( y = mx + 14 ) tangent to curve ( y = 12/x + 2 ).
Process
:
Set up and rearrange leading to ( m = -3 ).
Find intersection coordinates ( P(2, 8) ).
End of Lecture Notes.
📄
Full transcript