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Understanding Ball Toss Motion Dynamics
Apr 5, 2025
Lecture on Ball Toss Motion
Introduction
Discussion on the motion of a ball when it is tossed upwards.
Initial conditions:
Ball is thrown from a height of 1 meter.
Initial velocity of the ball is 10 m/s.
Gravity (g) = 9.8 m/s².
Key Concepts
Motion When Thrown Upwards
Velocity decreases as the ball ascends.
At the peak, the velocity is 0 but acceleration is still downward.
Acceleration is always downward.
Motion When Falling Down
Velocity and acceleration are in the same direction (downward), causing velocity to increase.
Equations and Calculations
Equation:
v² = v₀² - 2gh
Used to find the maximum height reached by the ball.
Final velocity v at peak = 0 m/s.
Initial velocity v₀ = 10 m/s.
Solved height (h) from throw to peak is 5.1 meters.
Total height from ground to peak = 6.1 meters.
Time to Reach Peak
Equation:
v = v₀ - gt
Solved time to reach peak (A to P) = 1.02 seconds.
Descent Time
Time from peak (P) back to initial height (B) is 1.02 seconds due to symmetry (ignoring air resistance).
Total Time in Air
Total time from initial height back to same height: 2.04 seconds (A to P to B).
Speed at Initial Height (B)
Speed at the returning point (B) without air resistance is the same as initial throw speed: 10 m/s.
Total Time to Reach Ground
Equation:
h = v₀t + ½gt²
Total time from peak (P) to ground (G) = 1.12 seconds.
Total air time from initial throw to ground = 2.14 seconds.
Speed Upon Hitting Ground
Equation:
v = √(2gh)
Speed upon impact with ground = 10.93 m/s (greater than initial throw speed due to downward acceleration).
Conclusion
Summary of the motion characteristics of a tossed ball.
Encouragement to like, share, and subscribe to the channel.
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