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Overview of Decidability and Undecidability
Dec 5, 2024
Lecture on Decidability and Undecidability Problems
Introduction
Recording for later review due to potential stream issues.
Overview of decidable problems: acceptance and emptiness problems for context-free grammars (CFGs).
Focus on undecidable problems: equality for CFGs, equality for Turing machines, and emptiness for Turing machines.
The ATM Problem
ATM Problem
: Acceptance problem for Turing machines.
Similar to ADFA (deterministic finite automata) and ACFG problems, but uses Turing machines.
Claim
: ATM is undecidable.
No algorithm to decide ATM, but it is recognizable.
Recognition
: If a Turing machine M accepts a string W, then accept.
Undecidability Proof
:
Use proof by contradiction.
Assume ATM is decidable and derive a contradiction.
Construct a contradictory machine D using a hypothetical decider H for ATM.
D performs the opposite of H; leads to contradictions when D runs on itself.
Conclude that ATM is undecidable.
Theorem: L is Decidable if and only if L and L-bar are Recognizable
If both a language and its complement are recognizable, the language is decidable.
Forward direction: If L is decidable, it is recognizable; L-bar is also recognizable.
Backward direction: Suppose A recognizes L, and B recognizes L-bar.
Simulate both machines; decide based on which accepts.
Consequence: ATM-bar is not recognizable because ATM is not decidable.
Visual Representation
Hierarchy of languages:
Regular, CFLs, Decidable, Recognizable, and Non-recognizable.
Position of ATM and ATM-bar in the hierarchy.
Emptiness Problem for Turing Machines (ETM)
ETM
: Check if the language of a Turing machine is empty.
Claim
: ETM is undecidable.
Use proof by contradiction; assume ETM is decidable and solve ATM.
Equivalence Problem for Turing Machines (EQTM)
EQTM
: Check if two Turing machines have the same language.
Claim
: EQTM is undecidable.
Use proof by contradiction; assume EQTM is decidable and solve ETM.
Introduction to Rice's Theorem
Rice's Theorem
: Every non-trivial property of Turing machine languages is undecidable.
Non-trivial Property
: Includes at least one Turing machine and excludes at least one.
Proof Strategy
:
Use a proof by contradiction to show the property is undecidable.
Example Application: 3TM
3TM
: Set of Turing machines with exactly three strings in their language.
Use Rice's Theorem to prove it is undecidable.
Linear Bounded Automaton (LBA)
Similar to Turing machines but with a bounded tape length.
Acceptance Problem for LBAs
: Decidable.
Finite number of configurations leads to a decision.
Emptiness Problem for LBAs (ELBA)
ELBA
: Check if the language of an LBA is empty.
Claim
: ELBA is undecidable.
Use proof by contradiction; simulate a computation history, show non-trivial property.
AllCFG Problem
AllCFG
: Check if a CFG generates all strings (sigma*).
Claim
: AllCFG is undecidable.
Use reversed computation histories and CFG properties.*
Equivalence Problem for CFGs (EQCFG)
EQCFG
: Check if two CFGs have the same language.
Claim
: EQCFG is undecidable.
Use all problem results to derive undecidability.
Summary of Decidability Results
Categories
: DFA, CFG/PDA, LBA, Turing machines.
Problems
: Acceptance, emptiness, equivalence, all-problem.
Results
: Various combinations of decidable and undecidable.
Conclusion
Comprehensive summary of decidability and undecidability across different computational models.
Open questions remain in computational complexity and language theory.
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