Transcript for:
Quadratic Zeros and Factoring

all right what I'd like to do is show you guys how to find the zeros of an equation 3x^2 + 7 x + 2 equal Z again the first thing I'm going to look at is determine what my A and C are and I showed you how to find the A and C in a previous video so a = 3 B = 7 and C = 2 now again I'm going to go ahead and use um My Little Diamond C of method to go and find my 8 * C which is 3 * 2 which becomes a 6 and my B which is going to be a seven so therefore I look at what two factors now are going to multiply to give me six but add to give me seven and when you think well there's only two there's only two different ways you can do 3 * 2 or 6 * one obviously you notice it's going to be 6 * one now what I'm going to do is I'm going to take these two factors and we're going to plug them into two binomials so we know that when factoring this equation when Factor this equation I'm going to have to I want to factor it into two different binomials so the way to one way to factor it into two binomials is you can take your a term and yes I know that 3x * 3x does not give you 3x^2 but just stay with me for right now and then you take what your two factors you had down here plus 6 and + one now if you notice now I out of this binomial I can fact actually factor out a three so if I factor out of three I'm left with an x + 2 * 3x + one then if I was to go ahead and reattempt and determine um and dis solve you I'm sorry Zer if I was to go ahead and multiply this through using my foil method I would get 3x^2 + 7x + 2 um and since I factor out of three that's just a common factor I can erase that out of my equation it's just an extra in there so a quick easy just Reep do your a times your C add it to get you your B find the two factors then take your a term put your two factors in the binomial and then factor out any common factors and then you have your answers now using the zero product property I have X + 2 = 0 and 3x + 1 = 0 therefore x = -2 and x = a 13 okay so that is how you find the zeros of an equation um given when a is greater than one