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Understanding Polynomial Long Division Techniques
Mar 10, 2025
Polynomial Long Division Overview
Basic Long Division Review
Example: 297 divided by 14
14 goes into 29 (2 times)
2 x 14 = 28
Subtract: 29 - 28 = 1
Bring down 7, making it 17
14 goes into 17 (1 time)
Subtract: 17 - 14 = 3
Result: 21 and 3/14
Long Division with Polynomials
Example 1: 2x³ ÷ (2x + 5)
Setup: 2x + 5 goes outside, 2x³ inside.
First term division:
2x into 2x³ = x²
Multiply: (2x + 5) x x² = 2x³ + 5x²
Subtract:
Result: 2x³ - 2x³ = 0
-7x² - 5x² = -12x²
Bring down 12x.
Repeat process:
2x into -12x² = -6x
Multiply: -6x(2x + 5) = -12x² - 30x
Subtract:
Result: -12x² + 12x² = 0
12x + 30x = 42x
Bring down remaining terms.
Final division:
2x into 18x = 9
Remainder: 0 (thus, 2x + 5 is a factor)
Example 2: Missing Terms
Ensure all polynomial degrees are represented (insert zeros for missing terms).
Example: x² terms missing in the polynomial.
Writing the Remainder
When not a factor:
Remainder format: (3x² - 4x + 9) + (4x - 4)/(x² + 1)
Synthetic Division
Use for linear factors.
Set x + 5 to zero: x = -5.
Coefficients: (4, 23, -16) for the polynomial.
Process:
Bring down first coefficient.
Multiply and add down the line.
Final result: Quotient and remainder.
Example 3: Synthetic Division with a Cubic Polynomial
Divide 2x³ - 3x² - 11x + 6 by x - 3.
Setup with coefficients.
Bring down and use addition for each step.
Remainder of 0 indicates that x - 3 is a factor.
Coefficients obtained lead to the quotient polynomial (2x² + 3x - 2).
Factor further if possible.
Common Pitfalls
Missing terms in polynomial division can lead to incorrect answers.
Always check for zero placeholders in synthetic division setup.
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