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Understanding U-Substitution in Calculus
Jan 21, 2025
U-Substitution for Definite Integrals
Key Concepts
U-substitution is a method used to find antiderivatives, particularly useful for definite and indefinite integrals.
The goal is to change variables from
x
to
u
to simplify integration.
Steps to follow:
Identify
u
and
du
.
Solve for
dx
in terms of
du
.
Substitute back into the integral, cancel terms if possible.
Integrate using the new variable
u
.
Substitute back the original variable.
Example Problems
Problem 1: ( \int 4x(x^2 + 5)^3 dx )
Choose:
( u = x^2 + 5 )
( du = 2x , dx )
Solve for ( dx: ) [ dx = \frac{du}{2x} ]
Substitute and simplify:
( \int 4x u^3 \frac{du}{2x} = 2 \int u^3 du )
Integrate:
( 2 \times \frac{u^4}{4} + C = \frac{1}{2} u^4 + C )
Substitute back:
Final Answer: ( \frac{1}{2} (x^2 + 5)^4 + C )
Problem 2: ( \int 8\cos(4x) , dx )
Choose:
( u = 4x )
( du = 4 , dx )
Solve for ( dx: ) [ dx = \frac{du}{4} ]
Substitute and simplify:
( \int 8\cos(u) \frac{du}{4} = 2 \int \cos(u) , du )
Integrate:
( 2\sin(u) + C )
Substitute back:
Final Answer: ( 2\sin(4x) + C )
Problem 3: ( \int x^3 e^{x^4} , dx )
Choose:
( u = x^4 )
( du = 4x^3 , dx )
Solve for ( dx: ) [ dx = \frac{du}{4x^3} ]
Substitute and simplify:
( \int e^u \frac{du}{4} = \frac{1}{4} \int e^u , du )
Integrate:
( \frac{1}{4}e^u + C )
Substitute back:
Final Answer: ( \frac{1}{4} e^{x^4} + C )
Problem 4: ( \int 8x \sqrt{40 - 2x^2} , dx )
Choose:
( u = 40 - 2x^2 )
( du = -4x , dx )
Solve for ( dx: ) [ dx = \frac{du}{-4x} ]
Substitute and simplify:
( \int 8x \sqrt{u} \frac{du}{-4x} = -2 \int u^{1/2} , du )
Integrate:
( -\frac{4}{3} u^{3/2} + C )
Substitute back:
Final Answer: ( -\frac{4}{3} (40 - 2x^2)^{3/2} + C )
Strategies
Choose
u
such that substitution simplifies the integral.
Isolate
dx
to avoid mistakes.
Replace all
x
variables with
u
variables.
Cancel terms to simplify.
Use power rule for integration: ( \int u^n du = \frac{u^{n+1}}{n+1} + C )
Additional Practice
Try integrating: ( \int x^3 (2 + x^4)^2 , dx )
Consider trying similar problems to reinforce learning.
Conclusion
U-substitution simplifies finding antiderivatives.
Practice with various functions to become proficient.
Always verify by differentiating the result to check correctness.
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