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Understanding Motion Through Graphs and Equations
Jul 31, 2024
Class 9 Chapter: Motion - Lecture Notes
Introduction
This is the final session on the chapter 'Motion'.
Focus on graphs, equations of motion (kinematic equations), and related problems.
Previous videos covered introductory concepts.
Motion Graphs
Types of Graphs
*
Distance-Time Graph (Position-Time Graph)*
Used to describe motion by plotting distance covered over time.
Examples: Cricket match run analysis.
Axes
: X-axis (Time), Y-axis (Distance).
Distance-Time Graph for Uniform Motion
Characteristics
: Straight line indicating equal distances covered in equal intervals of time.
Example Plot
:
1s => 2m
2s => 4m
3s => 6m
4s => 8m
5s => 10m
Key Points
:
Always consider time on the x-axis and distance on the y-axis.
Equal distances in equal intervals => Uniform Motion => Straight Line.
Distance-Time Graph for Non-Uniform Motion
Characteristics
: Curve indicating unequal distances covered in equal intervals of time.
Example Plot
:
2s => 1m
4s => 4m
6s => 9m
8s => 16m
10s => 25m
Key Points
:
Unequal distances in equal intervals => Non-Uniform Motion => Curve.
Uses of Distance-Time Graph
Speed Calculation
: Distance/Time.
E.g., at point A (Time = 2s, Distance = 4m) => Speed = 4m/2s = 2m/s.
Velocity Calculation
: Displacement/Time.
E.g., between points A and B (Distance A = 4m, Distance B = 8m, Time = 2s) => Velocity = (8m-4m)/(4s-2s) = 2m/s.
Velocity-Time Graph
Vt Graph for Uniform Motion
Characteristics
: Straight line parallel to the x-axis indicating constant velocity.
Example Plot
:
1s => 20m/s
2s => 20m/s
3s => 20m/s
4s => 20m/s
Key Points
: Constant velocity implies Uniform Motion.
Vt Graph for Non-Uniform Motion
Characteristics
: Inclined straight line indicating uniformly accelerated motion.
Example Plot
:
As time increases, velocity increases linearly.
Key Points
: Non-Uniform Motion with Uniform Acceleration => Straight Line.
Uses of Velocity-Time Graph
Displacement Calculation
: Area under the Vt graph.
Area of rectangle
: Length x Breadth.
Area of trapezium
: (1/2) x (Sum of parallel sides) x (Height).
Important Equations of Motion
First Equation: v = u + at
Derivation
: Using Vt graph.
Initial velocity (u), final velocity (v), time (t), acceleration (a).
Derived from the definition of acceleration (change in velocity over time).
Second Equation: s = ut + 1/2 at²
Derivation
: Using area under Vt graph.
Distance (s), initial velocity (u), time (t), acceleration (a).
Area of triangle + area of rectangle.
Third Equation: v² - u² = 2as
Derivation
: Using average velocity and basic definitions.
Derived from average velocity (v + u)/2 and displacement (s).
Solved Examples
Example 1: Train Motion
Given
:
Initial velocity (u) = 0 m/s
Final velocity (v) = 72 km/h = 20 m/s
Time (t) = 5 minutes = 300 seconds
Find Acceleration (a)
:
Using v = u + at
a = (v - u) / t = (20 - 0) / 300 = 1/15 m/s²
Find Distance (s)
:
Using s = ut + 1/2 at²
s = 0 + 1/2 * 1/15 * 300² = 3000 meters = 3 kilometers
Example 2: Car Braking
Given
:
Final velocity (v) = 0
Acceleration (a) = -6 m/s²
Time (t) = 2 seconds
Initial velocity (u) calculation
:
Using v = u + at
u = v - at = 0 - (-6 * 2) = 12 m/s
Find Distance (s)
:
Using s = ut + 1/2 at²
s = 12 * 2 + 1/2 * (-6) * 2² = 12 meters
Conclusion
Understanding motion graphs and equations is crucial.
Practice problems to master the concepts.
Stay tuned for the next chapter.
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