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Understanding VSEPR Theory and Molecular Shapes

Aug 14, 2024

Lecture Notes: VSEPR Theory for 5 Electron Clouds

Overview

  • Continued exploration of VSEPR theory for 5 electron clouds.
  • Focus on determining the shape of molecules with examples: Chlorine Trifluoride (ClF₃) and Triiodide Ion (I₃⁻).

Example 1: Chlorine Trifluoride (ClF₃)

Steps to Determine Molecular Shape

  1. Draw Dot Structure

    • Calculate total valence electrons:
      • Chlorine (Cl): 7 valence electrons (Group 7)
      • Fluorine (F): 3 atoms x 7 = 21
      • Total: 28 valence electrons
    • Chlorine is central (less electronegative than Fluorine).
    • Bond Cl to 3 F atoms, use 6 electrons, 22 electrons remain.
    • Assign remaining electrons to terminal atoms (F) to fulfill octet rule.
    • Remaining 4 electrons assigned as lone pairs on central Cl.
    • Chlorine exceeds octet rule due to its position in the third period.
  2. Count Electron Clouds

    • Electron clouds = regions of electron density (bonding & non-bonding).
    • Cl is surrounded by 5 electron clouds: 3 bonding pairs, 2 lone pairs.
  3. Predict Geometry

    • 5 electron clouds form a trigonal bipyramidal geometry.
    • Lone pairs take equatorial positions to minimize repulsion.
    • Final shape (ignoring lone pairs): T-shaped.
  4. Bond Angles

    • Ideal bond angles: 90° and 180° (actual may vary experimentally).

Key Points

  • Lone pairs take up more space than bonding pairs, influencing molecular shape.
  • Position lone pairs in equatorial positions to minimize repulsion.

Example 2: Triiodide Ion (I₃⁻)

Steps to Determine Molecular Shape

  1. Draw Dot Structure

    • Calculate total valence electrons:
      • Iodine (I): 7 x 3 = 21
      • Negative charge: +1 electron, total = 22 electrons
    • Bond 3 I atoms, use 4 electrons, 18 electrons remain.
    • Assign remaining electrons to terminal atoms and central atom as lone pairs.
    • Central Iodine accommodates extra electrons (expands valence shell).
    • Formal charge of central Iodine: -1.
  2. Count Electron Clouds

    • Total of 5 electron clouds around central Iodine: 2 bonding, 3 lone pairs.
  3. Predict Geometry

    • Electron clouds form trigonal bipyramidal arrangement.
    • Lone pairs in equatorial positions.
    • Final shape (ignoring lone pairs): Linear.
  4. Bond Angles

    • Predicted bond angle is approximately 180°.

Key Points

  • Dot structures help visualize electron distribution and formal charges.
  • Predicting shape involves considering only the bonded atoms after placing lone pairs.

Summary

  • Discussed two different molecules with 5 electron clouds and how lone pairs affect geometry.
  • Respective geometries depend on electron cloud arrangements and lone pair positions.
  • Examples illustrate how molecular shape is determined using VSEPR theory.