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Understanding Inclined Planes and Forces

Sep 3, 2024

Notes on Inclined Planes

Key Concepts

  • Inclined Plane Forces
    • Normal Force: Acts perpendicular to the surface.
    • Weight Force: Acts downward (negative y direction), represented as mg.

Triangle Representation

  • Draw a triangle based on the incline:
    • Angles:
      • Angle of incline: θ
      • Complementary angle: 90° - θ
      • If θ = 30°, then:
        • Angle adjacent to θ = 60°
        • Angles in triangle: 30°, 60°, 90°

Trigonometric Functions (SOHCAHTOA)

  • Use SOHCAHTOA to resolve forces:
    • Cosine:
      • cos(θ) = adjacent/hypotenuse
      • x = mg cos(θ)
      • Normal Force: N = mg cos(θ)
    • Sine:
      • sin(θ) = opposite/hypotenuse
      • y = mg sin(θ)
      • Force down incline (Fg): Fg = mg sin(θ)

Equations to Remember

  1. Normal Force:
    • N = mg cos(θ)
  2. Force Down the Incline:
    • Fg = mg sin(θ)

Acceleration on a Frictionless Incline

  • Only Fg acting in the x direction.
  • Using Newton's second law:
    • F = ma; Fg = mg sin(θ)
  • Therefore, acceleration (a) down the incline:
    • a = g sin(θ)
    • Independent of mass.

Inclined Plane with Friction

  • If kinetic friction is present:
    • Fk = μ_k * N
    • Net force for acceleration:
      • Net force = Fg - Fk
      • a = g sin(θ) - μ_k g cos(θ)

Block Sliding Up the Incline

  • If sliding up the incline:
    • Fg acting down the incline; Fk opposes motion.
    • Net force:
      • a = -g sin(θ) - μ_k g cos(θ)

Example Problems

Problem 1: Block Sliding Down a 30° Incline

  • To find acceleration:

    • Fg = mg sin(30°)
    • a = g sin(30°) = 4.9 m/s²
  • Distance = 200 m; find final speed:

    • Use kinematic equation:
      • V_final² = V_initial² + 2AD
      • V_final = √(0 + 2 * 4.9 * 200) = 44.27 m/s

Problem 2: Block Sliding Up a 25° Incline

  • Part A: Find acceleration:

    • Fg = mg sin(25°)
    • a = -g sin(25°) = -4.14166 m/s²
  • Part B: How far up will it go?

    • Use kinematic equation:
      • V_final² = V_initial² + 2AD
      • Distance D = 23.662 m
  • Part C: Time to stop:

    • Use equation:
      • V_final = V_initial + at
      • t = 3.38 seconds

Additional Resources

  • For more kinematic formulas, refer to online videos on the topic.