Jul 8, 2024
Initial Assumption:
6 + β2
is rational.a/b
, where a
and b
are integers.Derivation and Rationality:
6 + β2
as a/b
.β2 = (a - 6b)/b
, which means β2
is rational.β2
is irrational.6 + β2
must be irrational.**Conclusion:
6 + β2
is rational.6 + β2
is irrational.5 + β3
Initial Assumption:
5 + β3
is rational.a/b
where a
and b
are integers.Derivation and Rationality:
5 + β3 = a/b
.β3 = (a - 5b)/b
, which contradicts β3
being irrational.Conclusion:
5 + β3
is rational.5 + β3
is irrational.3 + 2β7
Initial Assumption:
3 + 2β7
is rational and can be written as a/b
.Derivation and Rationality:
3 + 2β7 = a/b
.2β7 = a/b - 3
and therefore β7 = (a - 3b)/(2b)
, which is rational.β7
is irrational.Conclusion:
3 + 2β7
is rational.3 + 2β7
is irrational.**Steps:
a/b
where a
and b
are coprime integers.Example: 5 - 7β2
5 - 7β2
is rational: express it as a/b
.7β2 = (a - 5b)/b
.β2
would be rational, contradicting its known irrationality.5 - 7β2
is irrational.