Jul 8, 2024
Initial Assumption:
6 + √2 is rational.a/b, where a and b are integers.Derivation and Rationality:
6 + √2 as a/b.√2 = (a - 6b)/b, which means √2 is rational.√2 is irrational.6 + √2 must be irrational.**Conclusion:
6 + √2 is rational.6 + √2 is irrational.**5 + √3Initial Assumption:
5 + √3 is rational.a/b where a and b are integers.Derivation and Rationality:
5 + √3 = a/b.√3 = (a - 5b)/b, which contradicts √3 being irrational.Conclusion:
5 + √3 is rational.5 + √3 is irrational.3 + 2√7Initial Assumption:
3 + 2√7 is rational and can be written as a/b.Derivation and Rationality:
3 + 2√7 = a/b.2√7 = a/b - 3 and therefore √7 = (a - 3b)/(2b), which is rational.√7 is irrational.Conclusion:
3 + 2√7 is rational.3 + 2√7 is irrational.**Steps:
a/b where a and b are coprime integers.Example: 5 - 7√2
5 - 7√2 is rational: express it as a/b.7√2 = (a - 5b)/b.√2 would be rational, contradicting its known irrationality.5 - 7√2 is irrational.**