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Integrating Rational Functions Simplified
Feb 8, 2025
Integration of Rational Functions Using Partial Fraction Decomposition
Introduction
Focus on integrating rational functions.
Use of partial fraction decomposition.
Factoring
Factor the denominator fully before decomposing.
Example: Difference of perfect squares.
( x^2 - 4 = (x + 2)(x - 2) ).
Difference between linear and quadratic factors.
Linear Factors:
( x, 3x, x + 4 ).
Quadratic Factors:
( x^2, x^2 + 3x ).
Partial Fraction Decomposition
Break a fraction into smaller fractions.
For linear factors: ( \frac{A}{x+2} + \frac{B}{x-2} ).
For quadratic factors: ( \frac{Ax+B}{x^2+8} ).
Example of Partial Fractions
Simplifying ( \frac{9}{20} ) into ( \frac{1}{4} + \frac{1}{5} ).
Process involves finding constants ( A, B, \ldots ).
Solving for Constants
Multiply by the denominator to eliminate fractions.
Use specific x-values to solve for constants.
Example: Solving for ( B ) by setting ( x = 2 ).
Solving for ( A ) by setting ( x = -2 ).
Integrating the Function
Antiderivative of ( \frac{1}{x} ) is ( \ln |x| ).
Example with constants: ( \frac{4}{x+7} ) becomes ( 4 \ln |x+7| ).
Properties of Logs
Combine logs: ( \ln a - \ln b = \ln \frac{a}{b} ).
Use in final integration expressions.
Practice Problems
Practice with quadratic and repeated factors.
Example: ( \frac{x-4}{x^2 + 2x - 15} ).
Factor the denominator and find ( A, B ).
Handling Quadratic or Repeated Factors
For quadratic: ( \frac{Ax+B}{x^2+4} ).
For repeated: Use multiple terms: ( \frac{A}{x-1} + \frac{B}{x-2} + \frac{C}{x-2^2} ).
Complex Example
Integrating ( \frac{x^2 + 9}{(x^2 - 1)(x^2 + 4)} ).
Factoring and decomposing for integration.
Use of ( \ln ) for linear terms and arctan for quadratic terms.
Trigonometric Substitution
Substitute in complex quadratic cases.
Example: ( x = 2\tan\theta ) leads to secant integration.
Final Result
Combine all partial results for a complete integral expression.
Use properties of logarithms to simplify results where possible.
Conclusion
Integration using partial fraction decomposition requires careful factorization and solving for constants.
Application of logarithmic properties aids in simplifying expressions.
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