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Percent Composition in Chemistry

Sep 12, 2025

Overview

This lecture explains how to calculate percent composition by mass for elements in a compound, using molecular formulas, atomic masses, and worked examples.

Percent Composition Formula

  • Percent composition is calculated as: (Mass of element / Total mass of compound) Γ— 100.
  • You can use either the masses in grams or molar masses (g/mol) for the calculation.

Example: Sucrose (C₁₂Hβ‚‚β‚‚O₁₁)

  • Find total molar mass: (12 Γ— 12.01) + (22 Γ— 1.008) + (11 Γ— 16) = 342.296 g/mol.
  • Carbon: (12 Γ— 12.01) / 342.296 Γ— 100 = 42.1%
  • Hydrogen: (22 Γ— 1.008) / 342.296 Γ— 100 = 6.5%
  • Oxygen: (11 Γ— 16) / 342.296 Γ— 100 = 51.4%
  • The percentages should add up to 100%.

Example: Cβ‚…H₉NOβ‚‚

  • Molar mass: (5 Γ— 12.01) + (9 Γ— 1.008) + (1 Γ— 14.01) + (2 Γ— 16) = 115.132 g/mol.
  • Carbon: 60.05 / 115.132 Γ— 100 = 52.16%
  • Hydrogen: 9.072 / 115.132 Γ— 100 = 7.88%
  • Nitrogen: 14.01 / 115.132 Γ— 100 = 12.17%
  • Oxygen: 32 / 115.132 Γ— 100 = 27.8%

Comparing Percent Carbon in Different Compounds

  • CHβ‚„: (12.01 / 16.042) Γ— 100 = 74.87%
  • Cβ‚‚H₇N: (24.02 / 45.086) Γ— 100 = 53.3%
  • Cβ‚…H₁₂O: (60.05 / 88.146) Γ— 100 = 68.1%
  • C₆H₁₂O₆: (72.06 / 180.156) Γ— 100 = 40%
  • COβ‚‚: (12.01 / 44.01) Γ— 100 = 27.3%
  • CHβ‚„ has the greatest percent by mass of carbon among the options.

Finding Molar Mass Given Mass Percent and Atoms

  • If a compound has one nitrogen atom and 13.32% nitrogen by mass: (14.01 / Molar mass) Γ— 100 = 13.32%
  • Rearranged: Molar mass = 14.01 / 0.1332 = 105.18 g/mol.

Key Terms & Definitions

  • Percent Composition β€” The percentage by mass of each element in a compound.
  • Molar Mass β€” The mass of one mole of a substance, usually in g/mol.
  • Atomic Mass β€” The mass of a single atom of an element, in atomic mass units (u) or g/mol.

Action Items / Next Steps

  • Practice calculating percent composition for assigned compounds.
  • Review periodic table for atomic masses.
  • Complete any related homework problems.