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Understanding Taylor and Maclaurin Series
May 11, 2025
Notes on Taylor and Maclaurin Series
Introduction to Series
Power Series
: A series in the form ( C_n \cdot X^n ) from 0 to infinity.
The sum of a power series can represent a function.
Coefficients in Power Series
We want to solve for coefficients in series of the form ( C_n (X - A)^n ).
If we evaluate ( F(A) ), all terms except ( C_0 ) become zero, so ( F(A) = C_0 ).
Finding Coefficients
First Derivative
:
Take the derivative of the function, ( F' ).
( C_0 ) goes to zero, leaving ( C_1 ).
If using the chain rule, the second coefficient is obtained as follows:
( F'(A) = C_1 )
Second Derivative
:
Second derivative ( F'' ):
( F''(A) = 2C_2 )
Thus, ( C_2 = \frac{F''(A)}{2} )
Higher Derivatives
:
The third derivative gives ( F'''(A) = 6C_3 )
Therefore, ( C_3 = \frac{F'''(A)}{6} )
This pattern continues:
General formula: ( C_n = \frac{F^{(n)}(A)}{n!} )
Where the ( n! ) is the factorial of n.
Taylor Series
The coefficients defined by: ( C_n = \frac{F^{(n)}(A)}{n!} )
The Taylor series is generated by the function: [ F(X) = \sum_{n=0}^{\infty} C_n (X - A)^n ]
Convergence occurs for ( |X - A| < \text{radius of convergence} )._
Special Case: Maclaurin Series
A Maclaurin series is a Taylor series at ( A = 0 ).
The series becomes: [ F(X) = F(0) + \frac{F'(0)}{1!}X + \frac{F''(0)}{2!}X^2 + \ldots ]
Example: Maclaurin Series for ( e^X )
The nth derivative of ( e^X ) is ( e^X ).
Evaluating at zero yields:
All derivatives equal 1 at zero.
Thus, the series becomes: [ \sum_{n=0}^{\infty} \frac{X^n}{n!} ]
This is the Maclaurin series for ( e^X )._
Radius of Convergence
Use the ratio test to find radius of convergence:
Set up as ( \frac{X^{n+1}}{(n+1)!} \cdot \frac{n!}{X^n} )
Results in ( \lim_{n \to \infty} \frac{|X|}{n+1} = 0 ) (converges for all ( X )).
Radius of convergence is infinite
._
Conclusion
Taylor series have many applications; definitions are foundational.
Prepare to explore more topics after this foundational knowledge.
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