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Clamper and Voltage Doubler Circuits Explained

Feb 12, 2025

Basic Electronics: Clamper and Voltage Doubler Circuits

Introduction

  • Discussing clamper circuits
  • Focus on negative level shift circuits
  • Combination of clamper and peak detector to create a voltage doubler circuit

Clamper Circuit Overview

  • New clamper circuit with reversed diode polarity
  • Ideal diode model: V_on = 0 volts
  • Input voltage: V_s(t) = V_m * sin(ωt) where V_m = 5 volts
    • V_s varies from +5V to -5V*

Key Observations

  1. Capacitor Charging:
    • When diode conducts, capacitor charges instantaneously.
    • V_c = V_s when diode conducts (since R_on is small).
  2. Capacitor Voltage Behavior:
    • V_c can only increase.
    • Maximum V_c is V_m (5 volts). After reaching max, it remains constant.
    • Output voltage: V_o(t) = V_s - V_m (negative level shift).

Graph Analysis

  • Initial condition: V_c is 0.
  • As V_s increases, diode conducts and V_c increases, coinciding with V_s.
  • Once V_c reaches V_m, the output shifts downward from V_s by V_m.

Clamper with Non-Ideal Diode (V_on = 0.7V)

  • Maximum V_c now is V_m - V_on = 4.3 volts.
  • Output now shifts:
    • V_o(t) = V_s - (V_m - V_on)
    • V_o(t) = V_s - 4.3 volts.
  • Output voltage clamps at 0.7 volts.

Voltage Doubler Circuit

  • Combination of clamper (positive level shift) and peak detector.
  • Input voltage: Sinusoidal from -V_m to +V_m.
  • Output of positive clamper shifts from 0 to 2V_m.
  • Peak detector detects peak: Output is a DC voltage of 2V_m.
    • Achieves voltage doubling from sinusoidal input.

Circuit Implementation

  • Basic setup:
    • C1 and D1 = Positive clamper
    • D2 and C2 = Peak detector

Waveform Analysis

  • For ideal diodes (V_on = 0V):
    • Input (Blue), Clamped (Green), Output (Pink).
    • Output builds up to 2V_m over a few cycles.
  • For non-ideal diodes (V_on = 0.7V):
    • Output shifts to 2V_m - 1.4V due to diode drops.

Circuit with Two Diodes

  • Similar to clamper, but has both charging and discharging paths for the capacitor.

Problem Statement

  • Input waveform from -V_m to +V_m (e.g., -10V to +10V).
  • High interval (t1) and low interval (t2); with diode I-V characteristics.
  • Find V_o(t) in steady state.

Key Time Constants

  • Charging: Ï„1 = R1 * C.
  • Discharging: Ï„2 = R2 * C.
  • Both Ï„1 and Ï„2 are much larger than t (steady state assumption).

Steady State Behavior

  • Capacitor voltage (V_c) is nearly constant in steady state due to large time constants.
  • Output voltage: V_o(t) = V_i(t) - V_c.

Example Calculation

  • Input: V_m = 10V, t1 = 0.25ms, t2 = 0.75ms, R1 = 5k, R2 = 10k, C = 10μF.
  • Confirm conditions: R1 * C = 50ms, R2 * C = 100ms (both much larger than t1 and t2).
  • Steady state value of V_c: ~ -2V.
  • Final output: V_o = V_i + 1.86V (positive shift of V_i).

Summary

  • Explored clamper and peak detector circuits for voltage doubling.
  • Analyzed diode circuits using steady-state assumptions and charge conservation.
  • Next class: Diodes in rectification (AC to DC conversion).

Key Terms

  • Clamper
  • Peak Detector
  • Voltage Doubler
  • Diode I-V Characteristics
  • Steady State Analysis