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Clamper and Voltage Doubler Circuits Explained
Feb 12, 2025
Basic Electronics: Clamper and Voltage Doubler Circuits
Introduction
Discussing clamper circuits
Focus on negative level shift circuits
Combination of clamper and peak detector to create a voltage doubler circuit
Clamper Circuit Overview
New clamper circuit with reversed diode polarity
Ideal diode model: V_on = 0 volts
Input voltage: V_s(t) = V_m * sin(ωt) where V_m = 5 volts
V_s varies from +5V to -5V*
Key Observations
Capacitor Charging
:
When diode conducts, capacitor charges instantaneously.
V_c = V_s when diode conducts (since R_on is small).
Capacitor Voltage Behavior
:
V_c can only increase.
Maximum V_c is V_m (5 volts). After reaching max, it remains constant.
Output voltage: V_o(t) = V_s - V_m (negative level shift).
Graph Analysis
Initial condition: V_c is 0.
As V_s increases, diode conducts and V_c increases, coinciding with V_s.
Once V_c reaches V_m, the output shifts downward from V_s by V_m.
Clamper with Non-Ideal Diode (V_on = 0.7V)
Maximum V_c now is V_m - V_on = 4.3 volts.
Output now shifts:
V_o(t) = V_s - (V_m - V_on)
V_o(t) = V_s - 4.3 volts.
Output voltage clamps at 0.7 volts.
Voltage Doubler Circuit
Combination of clamper (positive level shift) and peak detector.
Input voltage: Sinusoidal from -V_m to +V_m.
Output of positive clamper shifts from 0 to 2V_m.
Peak detector detects peak: Output is a DC voltage of 2V_m.
Achieves voltage doubling from sinusoidal input.
Circuit Implementation
Basic setup:
C1 and D1 = Positive clamper
D2 and C2 = Peak detector
Waveform Analysis
For ideal diodes (V_on = 0V):
Input (Blue), Clamped (Green), Output (Pink).
Output builds up to 2V_m over a few cycles.
For non-ideal diodes (V_on = 0.7V):
Output shifts to 2V_m - 1.4V due to diode drops.
Circuit with Two Diodes
Similar to clamper, but has both charging and discharging paths for the capacitor.
Problem Statement
Input waveform from -V_m to +V_m (e.g., -10V to +10V).
High interval (t1) and low interval (t2); with diode I-V characteristics.
Find V_o(t) in steady state.
Key Time Constants
Charging: τ1 = R1 * C.
Discharging: τ2 = R2 * C.
Both τ1 and τ2 are much larger than t (steady state assumption).
Steady State Behavior
Capacitor voltage (V_c) is nearly constant in steady state due to large time constants.
Output voltage: V_o(t) = V_i(t) - V_c.
Example Calculation
Input: V_m = 10V, t1 = 0.25ms, t2 = 0.75ms, R1 = 5k, R2 = 10k, C = 10μF.
Confirm conditions: R1 * C = 50ms, R2 * C = 100ms (both much larger than t1 and t2).
Steady state value of V_c: ~ -2V.
Final output: V_o = V_i + 1.86V (positive shift of V_i).
Summary
Explored clamper and peak detector circuits for voltage doubling.
Analyzed diode circuits using steady-state assumptions and charge conservation.
Next class: Diodes in rectification (AC to DC conversion).
Key Terms
Clamper
Peak Detector
Voltage Doubler
Diode I-V Characteristics
Steady State Analysis
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