Lecture on Solubility and Solution Equilibria
Equilibrium Process in Dissolution
- Dissolution of a solute in a solvent is an equilibrium process, similar to evaporation.
- Initially, the rate of dissolving is high as there are no dissolved ions to recrystallize.
- As ion concentration increases, recrystallization starts, leading to dynamic equilibrium.
- Dynamic Equilibrium: Rates of dissolution and recrystallization are equal.
Sodium Chloride Dissolution
- Sodium chloride dissociates into aqueous sodium and chloride ions in water.
- The process is reversible; ions can recombine to form solid sodium chloride.
Types of Solutions
- Saturated Solution: Rate of recrystallization equals the rate of dissolution.
- Unsaturated Solution: Less than equilibrium amount of solute; additional solute can dissolve.
- Supersaturated Solution: More solute dissolved than at equilibrium; unstable.
- Disturbance causes crystallization.
Supersaturated Solutions and Demonstrations
- Supersaturated solutions appear like water but crystallize upon disturbance.
- Hot Ice (Sodium Acetate): Crystallizes upon disturbance, exothermic.
- Demonstrated by videos showing crystallization upon disturbance.
Solubility and Temperature
- Solubility often increases with temperature for solids.
- Exceptions: Some compounds like cerium sulfate decrease in solubility with temperature.
- Recrystallization Process: Purifies solids by forming larger, purer crystals upon slow cooling.
Solubility of Gases
- Temperature Effect: Solubility decreases with increasing temperature.
- Example: Cold soda keeps fizz longer than warm soda.
- Pressure Effect: Solubility increases with pressure (Henry's Law).
- Releasing pressure from a soda causes gas to escape.
Environmental Impacts
- Temperature affects dissolved oxygen in water, impacting aquatic life.
- Thermal Pollution: Warm water discharge reduces dissolved oxygen levels, harming aquatic life.
Henry's Law
- Solubility of a gas is proportional to its partial pressure.
- Formula: ( S = k_H \times P )
- ( S ) = Solubility
- ( k_H ) = Henry's Law Constant
- ( P ) = Partial Pressure
Application and Calculations
- Example calculation of oxygen solubility in water using Henry's Law.
- Given: ( P_{O_2} = 0.21 ) atm, ( k_H = 1.3 \times 10^{-3} ) M/atm.
- Solubility ( S = 2.7 \times 10^{-4} ) moles/L._
Note: Understanding these concepts is crucial for applications in chemistry and environmental science, particularly in areas involving solution chemistry and gas solubility.