Basic Geometry Review

Jun 28, 2024

Basic Geometry Review for SAT, HT, and Final Exams

Common Shapes and Key Formulas

Circle

  • Radius (r): Distance from the center to any point on the circle
  • Diameter (D): Twice the radius, D = 2r
  • Circumference (C): Distance around the circle, C = 2πr
    • Example: r = 5, C = 2π*5 = 10π ≈ 31.416
  • Area (A): Space within the circle, A = πr²
    • Example: r = 5, A = π*5² = 25π ≈ 78.54
  • Chord: A line touching two points on the circle but not passing through the center

Square

  • Side length (s): Length of a side of the square
  • Area (A): Space within the square, A = s²
    • Example: s = 8, A = 8² = 64
  • Perimeter (P): Distance around the square, P = 4s
    • Example: s = 8, P = 4*8 = 32
  • Example Problem: Given area = 36, find perimeter
    • s² = 36 → s = 6, P = 4*6 = 24

Rectangle

  • Length (l): Longer side of the rectangle
  • Width (w): Shorter side of the rectangle
  • Area (A): Space within the rectangle, A = lw
    • Example: l = 10, w = 5, A = 10*5 = 50
  • Perimeter (P): Distance around the rectangle, P = 2l + 2w
    • Example: l = 10, w = 5, P = 210 + 25 = 30
  • Example Problem: Given area = 40 and l = 8, find perimeter
    • w = 40/8 = 5, P = 28 + 25 = 26
  • Complex Problem: Length is three more than twice the width, area = 44, find perimeter
    • Equation: l = 3 + 2w, A = lw = 44
    • Use substitution and factoring to solve: w = 4, l = 11
    • P = 211 + 24 = 30

Triangles

Right Triangle

  • Pythagorean Theorem: a² + b² = c²
  • Example 1: Legs = 3 and 4, find hypotenuse
    • a² + b² = 9 + 16 = 25 → c = √25 = 5
  • Example 2: Hypotenuse = 13, one leg = 5, find missing leg
    • Known right triangles: 3-4-5, 5-12-13, 7-24-25, etc.
    • a = 5, c = 13, solve for b: 5² + b² = 13² → b² = 169 - 25 = 144 → b = 12
  • Special Right Triangles:
    • 3-4-5
    • 5-12-13
    • 7-24-25
    • 8-15-17
    • 9-40-41
    • 11-60-61
  • Example 3: Hypotenuse = 10, one leg = 6, find missing leg
    • Scale of 3-4-5: x = 32, y = 42 → 6-8-10 triangle confirms missing side is 8

Application Problems

Finding Missing Sides in Right Triangles

  • Example 1: 7-24-25 triangle, missing side is 25
  • Example 2: 8-15-17 triangle, missing side is 8
  • Example 3: Scaled 3-4-5 triangle: (33, 43 = 9, 12), missing side is 12
  • Example 4: Incorrect data
  • Example 5: Scaled 5-12-13 triangle (52 = 10, 122 = 24, 13*2 = 26), missing side is 24
  • Example 6: Scaled 3-4-5 triangle (310 = 30, 410 = 40), missing side is 50

Rectangle Problem

  • Example: Rectangle ABCD with AB = 12 and AC = 13
    • Right triangle: one side 12, hypotenuse 13, missing side 5
    • Area = lw = 125 = 60

Additional Resources

  • ACT/SAT Math Videos: Look for more examples and practice problems on YouTube.