Lecture on Polynomials
Introduction
- Key Concepts Covered: Polynomials
- Solving important questions and tips/tricks
Zeros of a Polynomial
- Definition: Zeros of a polynomial are the values of X which make the polynomial zero.
- Example Polynomial: (P(x) = x^2 - 5x + 6)
- Set the polynomial to zero: (x^2 - 5x + 6 = 0)
- Factorize: (x^2 - 3x - 2x + 6 = 0)
- Results: ((x - 3)(x - 2) = 0)
- Zeros: (x = 2) or (x = 3)
Terms: Zeros and Roots
- Zeros and Roots of a polynomial are the same.
- To find zeros: Set polynomial (P(x)) to zero and solve for x.
Relation Between Zeros and Coefficients
- Quadratic Polynomial: (P(x) = ax^2 + bx + c)
- Relation:
- Sum of Roots: (\alpha + \beta = -\frac{b}{a})
- Product of Roots: (\alpha \beta = \frac{c}{a})
- Formula: Quadratic Polynomial in terms of roots:
- (x^2 - (\alpha + \beta)x + \alpha \beta)
Example Problem
- Polynomial: (\sqrt{3}x^2 - 8x + 4\sqrt{3})
- Set to zero and factorize: ((\sqrt{3}x)(x - 2\sqrt{3}) - 2(x - 2\sqrt{3}) = 0)
- Zeros: (x = \frac{2}{\sqrt{3}}) and (x = 2\sqrt{3})
- Verification: Use relations to confirm.
- Sum: (\alpha + \beta = 8/\sqrt{3})
- Product: (4)
Finding Coefficients
- If given roots, substitute and solve.
- Example: Roots (x = \frac{2}{3}) and (x = -3)
- Polynomial: (ax^2 + 7x + b = 0)
- Substitute roots to form equations.
- Solve equations to get coefficients a and b.
Important Points
- If a is a zero: ((x - a)) divides (P(x)).
- Example: Zero 2 for (P(x)) implies ((x - 2)) divides (P(x)).
Finding All Zeros
- Cubic Polynomial Example: (2x^3 + x^2 - 6x - 3)
- Given zeros: (\sqrt{3}) and (-\sqrt{3})
- Factors: (x - \sqrt{3} ) and (x + \sqrt{3})
- Find quotient by dividing: (2x + 1)
- Other zero: Solve (2x + 1 = 0), (x = -\frac{1}{2})
Dividing Polynomials
- Example: Polynomial (x^4 + 2x^3 + 8x^2 + 12x + 18) divided by (x^2 + 5).
- Quotient: (x^2 + 2x + 3)
- Remainder: (2x + 3)
- Coefficients: (P = 2, Q = 3)
Solving for Zeros in Expanded Form
- Example Polynomial: (x^2 + x - p(p+1))
- Factorize: ((x + p)(x - p) + (x - p) = 0)
- Zeros: Solve resulting equations.
Final Problem (Challenge)
- Equation: (ax^2 - 6x - 6 = 4)
- Solve to find values of a and b.
Conclusion
- Apply the techniques learned to solve polynomial questions.
- Practice is key!
- Visit Manoj Academy for more practice.
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