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Kinematic Equations of Accelerated Motion

Jun 17, 2024

Kinematic Equations of Accelerated Motion

Key Concepts

  • Instantaneous Velocity: The velocity of an object at a specific instant.
  • Instantaneous Acceleration: The rate of change of velocity at a specific instant.
  • Equations of Motion (Constant Acceleration):
    • u: Initial velocity
    • v: Final velocity
    • t: Time
    • s: Displacement
    • a: Acceleration (must be constant)
  • Calculus Method: Used for deriving equations when acceleration is not constant.
  • Average vs. Instantaneous Velocity:
    • Average Velocity: Total displacement divided by total time (Ī”s/Ī”t).
    • Instantaneous Velocity: Derivative of displacement with respect to time (ds/dt).
  • Velocity-Time Graph: Slope represents instantaneous velocity.
  • Displacement from Velocity: For constant velocity, s = vt. For variable velocity, integrate v dt.

Example Calculations

Finding Instantaneous and Average Velocity

  • Given: Displacement equation s = 5t² + 4t

  • Find: Instantaneous velocity at t = 2s

  • Solution:

    • Instantaneous Velocity: v = ds/dt = 10t + 4
    • At t = 2s: v = 24 m/s
  • Average Velocity: Between t = 2s and t = 3s

    • Calculate s at t = 3s and t = 2s
    • Use s2 - s1 over t2 - t1
    • Result: 29 m/s

Finding Displacement from Instantaneous Velocity

  • Given: Velocity equation v = 10t
  • Find: Displacement from 0 to 4s
  • Solution:
    • Integrate: s = ∫(0 to 4) 10t dt = 80m

Instantaneous Acceleration

  • Formula: a = dv/dt
  • Given: Displacement s = 5t² + 4t
  • Find: Instantaneous acceleration
  • Solution:
    • Find velocity: v = ds/dt = 10t + 4
    • Find acceleration: a = dv/dt = 10 m/s²

Deriving Equations of Motion Using Calculus

First Equation of Motion

  • Goal: Derive v = u + at
  • Start: a = dv/dt
  • Integrate: ∫(u to v) dv = ∫(0 to t) a dt
  • Result: v - u = at -> v = u + at

Second Equation of Motion

  • Goal: Derive s = ut + 1/2 at²
  • Start: v = ds/dt
  • Substitute: v = u + at
  • Integrate: ds = (u + at)dt
  • Result: s = ut + 1/2 at²

Third Equation of Motion

  • Goal: Derive v² = u² + 2as
  • Start: a = dv/dt
  • Eliminate: Time variable via a = v dv/ds
  • Integrate: a ∫(0 to s) ds = ∫(u to v) v dv
  • Result: v² = u² + 2as

Important Formulas Summary

  • Equations for Constant Acceleration:
    1. v = u + at
    2. s = ut + 1/2 at²
    3. v² = u² + 2as
  • Instantaneous Equations:
    • Instantaneous Velocity: ds/dt
    • Instantaneous Acceleration: dv/dt
    • Using Integration:
      • Displacement from Velocity: s = ∫v dt
      • Velocity from Acceleration: v = ∫a dt

Practice Question

  • Given: Displacement x = 6t + t³
  • Find: Acceleration at t = 5s
  • Try: Solve and leave answers in comments.

Conclusion

  • Practice regularly to master these concepts.
  • Check out Manoa Academy for full courses that include live classes, interactive videos, quizzes, and more.
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