Jun 17, 2024
u: Initial velocityv: Final velocityt: Times: Displacementa: Acceleration (must be constant)Īs/Īt).ds/dt).s = vt. For variable velocity, integrate v dt.Given: Displacement equation s = 5t² + 4t
Find: Instantaneous velocity at t = 2s
Solution:
v = ds/dt = 10t + 4t = 2s: v = 24 m/sAverage Velocity: Between t = 2s and t = 3s
s at t = 3s and t = 2ss2 - s1 over t2 - t129 m/sv = 10t0 to 4ss = ā«(0 to 4) 10t dt = 80ma = dv/dts = 5t² + 4tv = ds/dt = 10t + 4a = dv/dt = 10 m/s²v = u + ata = dv/dtā«(u to v) dv = ā«(0 to t) a dtv - u = at -> v = u + ats = ut + 1/2 at²v = ds/dtv = u + atds = (u + at)dts = ut + 1/2 at²v² = u² + 2asa = dv/dta = v dv/dsa ā«(0 to s) ds = ā«(u to v) v dvv² = u² + 2asv = u + ats = ut + 1/2 at²v² = u² + 2asInstantaneous Velocity: ds/dtInstantaneous Acceleration: dv/dts = ā«v dtv = ā«a dtx = 6t + t³t = 5s