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Mathematics Practice with Mr. Barrow
Mar 2, 2025
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Lesson 51: Additional Maths with Mr. Barrow
Overview
The lesson covers questions 1 to 10 of an OCR sample paper.
Students should attempt the questions before reviewing solutions.
Question 1: Recurrence Relation
Concept
: Sequence defined by ( u_{n+1} = 2u_n - 1 ).
Task
: Find the 6th term given the 3rd term is 12.
Process
:
4th term: ( 2 \times 12 - 1 = 23 )
5th term: ( 2 \times 23 - 1 = 45 )
6th term: ( 2 \times 45 - 1 = 89 )
Marks
: Method mark for finding intermediate terms, accuracy for the 6th term.
Practice
: Recurrence relations - Lesson 8._
Question 2: Binomial Expansion
Task
: Find the coefficient of ( x^3 ) in ((2 + 3x)^5).
Concept
: Binomial expansion involves choosing components to form a specific term.
Process
:
Use "5 choose 3" to find combinations.
Calculation: ( 3x^3 \times 2^2 \times 10 = 1080x^3 ).
Final Answer
: Coefficient is 1080.
Practice
: Binomial expansion - Lessons 23 & 24.
Question 3: Differentiation
Task
: Differentiate ( y = x^3 + 2x - 7 ) and show there are no turning points.
Solution
:
Differentiation
: ( \frac{dy}{dx} = 3x^2 + 2 )
Turning Points
: Solve ( 3x^2 + 2 = 0 ), no real solutions.
Marks
: Method for differentiation, showing no turning points.
Practice
: Differentiation and stationary points - Lesson 38.
Question 4: Integration
Task
: Integrate ( x^2 + 3 ) from 1 to 2.
Process
:
Integrate: ( \int (x^2 + 3) dx = \frac{x^3}{3} + 3x )
Evaluate from 1 to 2: ( (\frac{8}{3} + 6) - (\frac{1}{3} + 3) = \frac{16}{3} ).
Marks
: Integration and substitution method.
Practice
: Definite integration - Lesson 41.
Question 5: Trigonometry
Task
: Sketch ( h ) vs ( \theta ) graph, find expression for ( h ), solve for ( h = 100 ).
Concept
: Circular function and cosine relationship.
Process
:
Graph
: Sketch sine-like curve from 0 to 360°.
Expression
: ( h = 67.5 - 67.5 \cos \theta ).
Solve
: ( \theta = 118.8° ) or ( 241.2° ) when ( h = 100 ).
Practice
: Trigonometric equations - Lesson 14.
Question 6: Algebraic Fractions
Part A Task
: Simplify ( \frac{x}{x+2} - \frac{6}{x-1} ).
Solution
:
Common denominator: ( (x+2)(x-1) )
Result: ( \frac{x^2 - 7x - 12}{x^2 + x - 2} )
Part B Task
: Solve ( \frac{x^2 - 7x - 12}{x^2 + x - 2} = 4 ).
Solution
: Use quadratic formula to solve resulting equation.
Practice
: Algebraic fractions - Lesson 1.
Question 7: Completing the Square
Task
: Convert ( 2x^2 + 8x - 12 ) to completed square form, find minimum value.
Solution
:
Completed form: ( 2(x+2)^2 - 20 ).
Minimum value is (-20).
Practice
: Completing the square - Lesson 5.
Question 8: Cosine Rule
Task
: Show one angle in triangle is 60°.
Solution
:
Use cosine rule for angle opposite 7 cm side.
( \cos \theta = \frac{1}{2} ), hence ( \theta = 60° ).
Question 9: Factor Theorem
Part A
: Show ( x-3 ) is a factor of ( x^3 - 5x^2 + x + 15 ).
Substitute 3 into the polynomial; it equals 0.
Part B
: Solve cubic equation using factorization and quadratic formula.
Practice
: Factor theorem - Lesson 4.
Question 10: Permutations
Task
: Calculate number of passcodes with specific conditions.
Part A
: No restrictions: ( 7^4 = 2,401 ).
Part B
: With exactly 2 letters and 2 digits:
Calculate possible choices: 18 options for character selection.
Arrange in ( 4! ) ways: Total = 432.
Practice
: Permutations and combinations - Lessons 20-22.
Next Steps
Next lesson will cover questions 11-16 of the OCR sample paper. Ensure to attempt these questions before reviewing solutions.
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