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Kinematics and Motion Concepts

Sep 19, 2025

Overview

This lecture covers solving kinematics problems involving displacement, distance, and turning points using constant acceleration equations, discusses a classic "chasing" problem with two moving objects, and introduces vertical (1D) motion under gravity.

Displacement and Turning Points (Homework 1.9 Parts C & D)

  • An object moves left with a negative initial velocity and later right with a positive final velocity, indicating a turning point where velocity is zero.
  • Displacement (Δx) is calculated as x_final − x_initial, regardless of the path taken or turning points.
  • The kinematic equation used: v_f² = v_i² + 2aΔx.
  • For distance, split the motion at the turning point: calculate Δx₁ (to turning point) and Δx₂ (from turning point onward).
  • Total distance = |Δx₁| + |Δx₂|; distance ignores direction, only magnitude.
  • On a velocity-time (v-t) graph, area under the line (considering sign) represents displacement; sum of absolute areas gives distance.
  • Displacement equals the sum of Δx₁ and Δx₂ (with signs), while distance is the sum of their magnitudes.

Chasing Problem (Homework Question 10)

  • Two people: Person A at rest (starts with 0 velocity, constant acceleration after a delay), Person B moves at constant speed.
  • Both share a synchronized clock; Person A starts chasing after Person B passes by.
  • At the catch-up point, Person A and B have the same final position.
  • Write equations for positions:
    • Person A: x_A = (1/2)·a·t² (starts from rest)
    • Person B: x_B = v_B·t_delay + v_B·t
  • Set x_A = x_B to form a quadratic equation in t (the catch-up time).
  • Solve for t using the quadratic formula; discard non-physical (negative) roots.
  • Distance traveled by A is simply x_A using calculated t.

Introduction to Vertical Motion (Section 8)

  • Now considering motion under gravity: an object thrown vertically with initial velocity.
  • Only force acting is gravity (constant acceleration, a_y = −9.8 m/s²).
  • At the highest point, velocity is zero (turning point); after, object moves down.
  • The four kinematic equations still apply, with appropriate axis and sign convention (up is positive).
  • Will rewrite kinematic equations for vertical (y) motion in next lecture.

Key Terms & Definitions

  • Displacement (Δx) — The straight-line change in position; x_final − x_initial.
  • Distance — Total path length traveled, regardless of direction (sum of absolute displacements).
  • Turning Point — Moment when velocity changes sign (often where an object stops briefly).
  • Constant Acceleration — Acceleration that does not change over time.
  • Kinematic Equations — Four standard equations relating position, velocity, acceleration, and time for constant acceleration.
  • v-t Graph — Velocity versus time graph; area under the curve equals displacement.

Action Items / Next Steps

  • Complete homework problems 1–11 (up to the end of Section 7).
  • Begin reading Section 8 ("3D Falling Motion") in the textbook.
  • Watch the video derivation of the four kinematic equations if you missed the previous lecture.